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3 years ago

Write 308 as a product of its prime factor

2 answers:

6 0

308= 2 and 154= 2 and 77= 7 and 11
Answer: 2x2x7x11(can be simplified into 2^2x7x11)
In the answer you only use the prime numbers until you cannot divide any longer

AfilCa [17]3 years ago

3 0

Answer:

Solution: Since, the prime factors of 308 are 2, 7, 11. Therefore, the product of prime factors = 2 × 7 × 11 = 154.

Step-by-step explanation:

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F(x) = -x² - 7x - 5<br>Find f(-5)

irga5000 [103]

Answer:

Step-by-step explanation:

f(-5)=-(-5)^2 - 7(-5) - 5

f(-5)= -25 +35 - 5

f(-5) = -25 +30

f(-5) = 5

7 0

2 years ago

Read 2 more answers

A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg

polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

$P(X = x) = nCx p^{x} q^{n - x}$

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662$

Finally, the probability that 2 or fewer students will withdraw is

$P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355$

b) Compute the probability that exactly 4 will withdraw.

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304$

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716$

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0

3 years ago

Evan earns $18 per hour. how much will he earn per hour if he gets a 5% raise?

agasfer [191]

18·0.05= 0.9
0.9+18= 18.90
Even will earn $18.90 dollars an hour.

6 0

3 years ago

Let f(x) = x2- 3x - 7. Find f(-3)

Alexxx [7]

F(x) = x^2 - 3x - 7
f(-3) = (-3)^ 2 - 3(-3) - 7
f(-3) = 9 + 9 - 7
f(-3) = 18 - 7
f(-3) = 11

6 0

3 years ago

The following data gives the scores of 13 students in a Biostatistics exam. 75 80 28 70 95 82 75 64 61 90 81 65 91 a) Find the f

Radda [10]

Answer:The following data gives the scores of 13 students in a Biostatistics exam. 75 80 28 70 95 82 75 64 61 90 81 65 91 a) Find the following statistical measures 1. Mean 2. Median 3. Mode 4. Range 5. 34th percentile 6. Interquartile Range 7. Variance 8. Standard deviation PRINCIPLES OF STATISTICS Assignment (1) Due Date: 15/7/2020 9. Coefficient of variation. b) (Without Calculations) If the instructor decide to add up 5 marks for every student, what are the values of the statistical measures mentioned in part (a). c) Construct the Boxplot of students' scores, and identify any possible outliers.

6 0

3 years ago