This is distance formula is sqr. root of (x1-x2)^2 + (y1-y2)^2
(3-(-4))^2+ (-94-(-195))
7^2 101^2
49+ 10,201
square root of 10250
101.242 or the closest answer to this
A there are no real zeros
using the discriminant b² - 4ac to determine the nature of the zeros
for y = x² + 4x + 5 ( with a = 1, b = 4 and c = 5 )
• If b² - 4ac > 0 there are 2 real and distinct zeros
• If b² - 4ac = 0 there is a real and equal zero
• If b² - 4ac < 0 there are no real zeros
b² - 4ac = 16 - 20 = - 4
Since discriminant < 0 there are no real zeros
Answer:
Step-by-step explanation:
This is a right angled triangles and the summation of the other two angles must equal 90°
OR you can also say that the summation of all the angles in a ∆ must give us 180°
Therefore (2x+14) + (4x-26) = 90°
Expanding... By collecting all like terms, we have
2x+4x+14-26-90 = 0
6x - 102° = 0
Therefore, 6x = 102
x = 102/6
x = 17°
Answer:
It has been a while. I think it is ASA and AAS