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inessss [21]
1 year ago
7

Discuss the order of operations to explain why the expressions [(12÷(2+ 2)] ^3 and (12 ÷ 2) + 2^3 do not havethe same value.

Mathematics
1 answer:
Volgvan1 year ago
5 0

The order of operations are different. Hence, the answers are not equal

Explanation:

Oder of operations using PEMDAS (Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction)

[(12÷(2 + 2)]³ and (12 ÷ 2) + 2³

we solve seperately:

[(12÷(2+ 2)]³

we solve the parenthesis first:

(12 ÷ 4)³

then we apply division:

= (3)³

Then expand the exponent:

= 27

(12 ÷ 2) + 2³

we solve the parenthesis first:

6 + 2³

we expand the exponent:

6 + 8

we apply addition:

14

The order of operations are differnt. Hence, the answers are not equal

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Step-by-step explanation:

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3 years ago
A point R (-2,5) is mapped to point R',as described by a translation of 6 units to the rights and 7 units down.Mark R' on the co
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(4, -2)

Step-by-step explanation:

Given a point R (-2,5), if the point R' is described by a translation of 6 units to the rights and 7 units down, then the coordinate of R' will be;

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7 units down is towards the negative y axis

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4 0
2 years ago
Consider the equation below.
Eduardwww [97]

Answer:

The equation has no solutions .

Step-by-step explanation:

Given as :

<u>The linear equation is </u>

\dfrac{3}{4}(24 -16 x) = \dfrac{-2}{3}(18 x -27)

Or, \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x -  \dfrac{-2}{3} × 27

Or,  \dfrac{3}{4} ×24 - \dfrac{3}{4} × 16 x =  \dfrac{-2}{3} × 18 x + \dfrac{2}{3} × 27

Or, \frac{3\times 24}{4} -  \frac{3\times 16 x}{4} =  \frac{-2\times 18 x}{3} + \frac{2\times 27 x}{3}

Or, 3 × 6 - 3 × 4 x = - 2 × 6 x + 2 × 9

Or, 18 - 12 x = - 12 x + 18

Or, 18 - 18 = - 12 x + 12 x

or, 0 = 0

∵ The linear equation has no variables , so the equation has no solution

Hence,The equation has no solutions . Answer

8 0
2 years ago
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