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suter [353]
2 years ago
10

Question 2 (5 points) What is the value of x? HELP ASAP

Mathematics
1 answer:
Anton [14]2 years ago
3 0

Step-by-step explanation:

In \:  \triangle HDT,  \: BM || DT.. (given)  \\  \\  \therefore \:  \frac{HM}{MT} =  \frac{ HB}{ BD} \\ (by \: basic \: proportionality \: theorem) \\  \therefore \:  \frac{6}{x} =  \frac{9}{15} \\  \\  \therefore \:  x=  \frac{15 \times 6}{9} \\  \\  \therefore \:  x=  \frac{90}{9} \\  \\ \therefore \:  x=  10 \\  \\

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Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6
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<h2>Answer</h2>

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

Or as ordered pairs: (\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)

<h2>Explanation</h2>

Lets solve our system of equations  step by step

x^2+y^2=6 equation (1)

x^2-y=6 equation (2)

1. Solve for x^2 in equation (2)

x^2-y=6

x^2=6+y equation (3)

2. Replace equation (3) in equation (1) and solve for y

x^2+y^2=6

6+y+y^2=6

y^2+y=0

y(y+1)=0

y=0 or y=-1

3. Replace the values of y in equation (3) and solve for x

- For y=0

x^2=6+y

x^2=6

x=\sqrt{6} or x=-\sqrt{6}

- For y=-1

x^2=6+y

x^2=6-1

x^2=5

x=\sqrt{5} or x=-\sqrt{5}

So, the solutions of our system of equation are:

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

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