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3 years ago

Question 2 (5 points) What is the value of x? HELP ASAP

Mathematics

1 answer:

Anton [14]3 years ago

3 0

Step-by-step explanation:

$In \: \triangle HDT, \: BM || DT.. (given) \\ \\ \therefore \: \frac{HM}{MT} = \frac{ HB}{ BD} \\ (by \: basic \: proportionality \: theorem) \\ \therefore \: \frac{6}{x} = \frac{9}{15} \\ \\ \therefore \: x= \frac{15 \times 6}{9} \\ \\ \therefore \: x= \frac{90}{9} \\ \\ \therefore \: x= 10 \\ \\$

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the difference between a number and two times a number is seven the number is greater than zero what is the number

bagirrra123 [75]

7 is the answer

2x - x = 7
x = 7

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4 years ago

Which shows the following expression after the negative exponents have been eliminated? xy^-6/x^-4 y^2, x=/0 y=/0

Tom [10]

For this case we have the following expression:
(xy ^ -6) / (x ^ -4y ^ 2)
By power properties we can rewrite the expression as:
(x * x ^ 4) / (y ^ 6 * y ^ 2)
Then, for power properties:
Same exponents are added:
(x ^ (4 + 1)) / (y ^ (6 + 2))
(x ^ 5) / (y ^ 8)
Answer:
An expression after the negative exponents have been eliminated is:
(x ^ 5) / (y ^ 8)

3 0

3 years ago

Read 2 more answers

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

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2 years ago

Cos w, if tan w=-10/9 and sin w> 0

Veseljchak [2.6K]

Answer:

tan(x)=512 can be thought of as the ratio of opposite to adjacent sides in a triangle with sides 5,12 and 13 (where 13 is derived

Step-by-step explanation:

5 0

3 years ago

Is 1/8 less than 1/6?

trasher [3.6K]

1/8 or 1/6
which is greater

1) Lets make the fraction into a percent
1/8 ⇒ 1 ÷ 8 = 0.125
0.125 x 100 = 12.5%

1/6 ⇒ 1 ÷ 6 = 0.16....
0.16.. x 100 = 16.6.. = 16.7%

1/8 is bigger since it is closer to 0.

Hope this helps

4 0

3 years ago