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wariber [46]
3 years ago
12

Paul is making loaves of raisin bread to sell at a fundraiser event. The recipe calls for one third cup of raisins for each loaf

, and Paul has three and one fourth cups of raisins. How many cups of raisins will he have left over?
Mathematics
1 answer:
Dafna1 [17]3 years ago
7 0
He will have a fourth of a cup raisins left over<span />
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Find the range of the function y=-x^2-3x when the domain is {-5,0,2}
umka21 [38]

Answer: \{-10, 0 \}

Step-by-step explanation:

The range is the set of output values for the domain (the set of inputs).

  • When x=-5, y=-(-5)^{2}-3(-5)=-10.
  • When x=0, y=-0^{2}-3(0)=0.
  • When x=2, y=-2^{2}-3(2)=-10

So, the range is \boxed{\{-10, 0 \}}

4 0
2 years ago
Humihingi po ako sa inyo ng tulong po, sana matulungan nyo po ako dito☝​
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Step-by-step explanation:

3 0
3 years ago
Help with this please
aliina [53]
AB = 6 cm, AC = 12 cm, CD = ?

In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.

Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°

In order to find ∠BCA, use the law of sines:
 
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA

Now add ∠BCA (30°) to ∠DCB = 35° to find ∠DCA.
∠DCA = 30 + 35 = 65°

Since triangle DCA has 180°, we know ∠CAD = 180 - ∠DCA - ∠ADC = 180 - 65 - 55 = 60°

In triangle DCA we now have all three angles and one side, so we can use the law of sines to find the length of DC.

12cm/sin(∠ADC) = DC/sin(∠DCA)
12cm/sin(55°) = DC/sin(60°)
DC = 12cm*sin(60°)/sin(55°)
DC = 12.686 cm
3 0
3 years ago
4. The reflecting dish of a parabolic microphone has a cross-section in the shape of a parabola. The microphone itself is placed
elixir [45]
Assume the parabola is placed on a graph where the x-axis is the top of the dish.
The vertex is then at (0,-30)  The x-intercepts or zeros are at (-30,0) and (30,0)

The equation of such parabola would be:
y = a(x+30)(x-30)
Plug in vertex to find value of 'a'
-30 = a(0+30)(0-30) \\  \\ a = \frac{-30}{(-30)(30)} = \frac{1}{30}

Now find the focus given that p = \frac{1}{4a}
p = \frac{1}{4(1/30)} = \frac{30}{4} = 7.5

Answer: the microphone should be placed 7.5 inches from vertex.
8 0
3 years ago
What is 5/9 divided by 5 ?
SpyIntel [72]

Answer:

5/45 or 1/9 simplified

3 0
3 years ago
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