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3 years ago

What is 256 square root??

Mathematics

2 answers:

Digiron [165]3 years ago

5 0

Answer: 16

Step-by-step explanation: √

256=16

at least that's the positive square root

−16

is also a square root of 256.

16²=(−16)2=256

By definition, the principal square root of a number is the positive square root. The term "the square root" is commonly used to refer to the principal (positive) root though there are usually two roots.

kondor19780726 [428]3 years ago

3 0

Answer:

Step-by-step explanation:

$\sqrt{256} \\=\sqrt{16 * 16} \\=16$

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Two right angles are complementary

Y_Kistochka [10]

Angles are complementary when they add up to 90 degrees. For example 60 and 30, or 45 and 45.
Angles are supplementary when they add up to 180 degrees. For example 90 and 90, or 100 and 80.

Hope that helps

7 0

3 years ago

Read 2 more answers

Derek and Mia place two green marbles and one yellow marble in a bag. Somebody picks a marble out of the bag without looking and

cluponka [151]

Answer:

Thus, the expected value of points for Derek and Mia are $\dfrac{-1}{9}$ and $\dfrac{1}{9}$ respectively.

Step-by-step explanation:

Number of green marbles = 2 and Number of Yellow marbles = 1

Then, total number of marbles = 2+1 = 3

A person selects two marbles one after another after replacing them.

So, the probabilities of selecting different combinations of colors are,

$1.\ P(GG)=P(G)\times P(G)\\\\P(GG)=\dfrac{2}{3}\times \dfrac{2}{3}\\\\P(GG)=\dfrac{4}{9}$

$2.\ P(GY)=P(G)\times P(Y)\\\\P(GY)=\dfrac{2}{3}\times \dfrac{1}{3}\\\\P(GY)=\dfrac{2}{9}$

$3.\ P(YG)=P(Y)\times P(G)\\\\P(YG)=\dfrac{1}{3}\times \dfrac{2}{3}\\\\P(YG)=\dfrac{2}{9}$

$4.\ P(YY)=P(Y)\times P(Y)\\\\P(YY)=\dfrac{1}{3}\times \dfrac{1}{3}\\\\P(YY)=\dfrac{1}{9}$

Now, we have that,

If two marbles are of same color, then Mia gains 1 point and Derek loses 1 point.

If two marbles are of different color, then Derek gains 1 point and Mia loses 1 point.

<h3>Also, the expected value of a random variable X is $E(X)=\sum_{i=1}^{n} x_i\times P(x_i)$ .</h3>

Then, the expected value of points for Derek is,

$E(D)= (-1)\times \dfrac{4}{9}+1\times \dfrac{2}{9}+1\times \dfrac{2}{9}+(-1)\times \dfrac{1}{9}\\\\E(D)= \dfrac{-5}{9}+\dfrac{4}{9}\\\\E(D)=\dfrac{-1}{9}$

And the expected value of points for Mia is,

$E(M)= 1\times \dfrac{4}{9}+(-1)\times \dfrac{2}{9}+(-1)\times \dfrac{2}{9}+1\times \dfrac{1}{9}\\\\E(M)= \dfrac{5}{9}-\dfrac{4}{9}\\\\E(M)=\dfrac{1}{9}$ .