The percentage of runners that have times less than 14.4 seconds that is P(x<14.4) is 0.0013499 which is approximately = 0.15%.
<h2>What is standard deviation?</h2>
The standard deviation of a data set is defined as how the data is dispersed in relation to the mean.
From the question,
The raw time given (X) = 14.4 sec
The mean value(m) = 18sec
The standard deviation(d) = 1.2 sec
Using the formula,
z = X - m/ d
z= 14.4- 18/1.2
z = -3.6/1.2
z= -3
Using a Z table to find the percentage equivalent of P(x<14.4) is 0.0013499 which is approximately = 0.15%.
Therefore, the percentage of runners that have times less than 14.4 seconds that is P(x<14.4) is 0.0013499 which is approximately = 0.15%.
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Answer:
see explanation
Step-by-step explanation:
the translation (x, y) → (x - 4, y + 7)
means subtract 4 from the x-coordinate and add 7 to the y-coordinate of the original coordinate points
R(0, - 4 ) → R'(0 - 4, - 4 + 7 ) → R'(- 4, 3 )
S(- 2, - 1 ) → S'(- 2 - 4, - 1 + 7 ) → S'(- 6, 6 )
T(- 6, 1 ) → T'(- 6 - 4, 1 + 7 ) → T'(- 10, 8 )
Answer:
Equation: 2.35x+5.50=89.50
ANSWER FOR A.) 95.8
Step-by-step explanation:
A.) 2.35×8=18.8
5.50×14=77
18.8×77=95.8
Answer: 27%
Step-by-step explanation:
Question A:
Rewriting the table for f(x):
x -1 0 1
f(x) -7 -1 5
Notice that for every increase of one unit in 'x', there are an increase 6 units on f(x). Hence, the gradient of the slope of f(x) is 6.
g(x) = 5x - 4 ⇒ This function follows the general form of the straight line equation, y = mx + c, where 'm' is the gradient and 'c' is the y-intercept.
Hence, the gradient of the slope of g(x) is 5.
The slope of f(x) is steeper than the slope of g(x).
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Question B:
The y-intercept is the value of y where a straight line crosses the y-axis (or when x is zero).
From the table of f(x), the y-intercept is -1 (this is the value of 'y' when 'x' is zero)
From the given function g(x) = 5x - 4, the y-intercept is -4.
f(x) has a greater y-intercept.
