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yarga [219]
3 years ago
11

Simplify. i5i3i11i7 asap

Mathematics
1 answer:
Otrada [13]3 years ago
5 0
Idk if I can simplify that
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Please help, need for math hw and cant figure it out
swat32

The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2

<h3>How to represent the quadratic function in standard form?</h3>

The quadratic function is given as

f(x) = -3x^2 + 6x - 2

The standard form of a quadratic function is represented as:

f(x) = ax^2 + bx + c

When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form

Where

a = -3

b = 6

c = -2

Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2

Read more about quadratic function at

brainly.com/question/25841119

#SPJ1

7 0
1 year ago
Can people help me please to find the volume about question number 10 please and tell me the answer step by step please I need h
Alecsey [184]
#10
Volume of a cylinder: \pir²h

Plug the numbers in.

\pi3²15 = <span>424
</span>
The volume of the pipe is 424 cm³.
7 0
3 years ago
ANSWER ALL 5 PARTS.
N76 [4]
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

6 0
3 years ago
Mary earns $277.30 tutoring. If she works for 23.5 hours, how much money does
PIT_PIT [208]

Answer: $16.06 (rounded to nearest cent)

Step-by-step explanation:

3 0
2 years ago
Can you help me with this? 2 - -(-1/8) + -7/4
den301095 [7]

Hello!

Note that when seeing an odd number of negatives next to each other, it will remain negative, while having an even number would be positive. For example, -- is +, while --- is -.

Based on this information, we can rewrite the equation below.

2-1/8-7/4

Let's rewrite 7/4 out of 8.

2-1/8-14/8

2-15/8

Let's rewrite 2 as an improper fraction.

16/8-15/8=1/8

Therefore, our answer is 1/8.

3 0
3 years ago
Read 2 more answers
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