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Feliz [49]
3 years ago
12

I need only 16 and 17 please help

Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0

9514 1404 393

Answer:

  16. a: (-90°, (4, 3)); b: (90°, (0, 3)); c: (-90°, (0, 0))

  17. a: (down, (4, -1)); b: (right, (4, 3)); c: (up, (5, 2))

Step-by-step explanation:

We don't know what notation you're used to seeing for rotations. Here. we'll use the form [degrees CCW, (center)]. (CW angles are negative.) In any rotation, the center is the point that is invariant (remains in the same place)

16.

a) The tail is invariant, so the rotation is (-90°, (4, 3)).

b) The tip is invariant, so the rotation is (90°, (0, 3)).

c) The origin is invariant, so the rotation is (-90°, (0, 0))

__

17.

a) The tail is invariant, so the arrow is pointing down with the tip at (4, -1).

b) The center is invariant, so the arrow is reversed. It is pointing right with the tip at (4, 3).

c) Point (2, 3) is invariant, so the arrow is pointing up with the center at (5, 0). The tip is at (5, 2).

_____

<em>Additional comment</em>

If you have trouble visualizing these rotations, you might find it useful to trace the arrow on a piece of (semi-)transparent medium (plastic or tracing paper) so that you can move it as required to match the descriptions in the problem statement. A pin, or a dot on your tracing, can serve to fix the center of rotation. A little hands-on never hurts in math and geometry.

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In a certain town, 80% of all married men are working, and 75% of all married men are over 35 years old. Among working married m
hram777 [196]

It helps to set up a two way table as shown below. Such tables compare 2 different variables. In this case, we're comparing the variables "working status" and "age".

Specifically, the working status separates the men into "working vs non-working". The age variable splits the men into groups of "35 or younger" and "over 35". Usually, but not always, each variable will take on two values.

Let's say this town had 1000 married men. 80% of this is 0.80*1000 = 800 to indicate there are 800 married working men. So we write this in the "total" column for the "working" row. This leaves 1000-800 = 200 nonworking married men, which will go right under the 800.

We're told that 75% of the married men are over 35, so 0.75*1000 = 750 married men are over 35. This goes in the "total" row for the "over 35" column. There are 1000-750 = 250 married men who are 35 and under.

As you can see, the stuff in the total column and the total row must add back to the grand total of 1000 married men overall.

--------------------------------

Another bit of info given is that "Among the working married men, 70% are over 35". We'll only focus on the "working" row. We have 800 total and 70% of this is 0.70*800 = 560 which is the number of working married men over 35. This leaves 800-560 = 240 married men who are not over 35.

At this point, we have 2 spots left in the table. Through guess and check, or using algebra, you should find that there are 190 non-working men over 35 and 10 non-working men who aren't over 35. Make sure that each row and column total checks out.

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By now, the table is fully filled out. See below.

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3 years ago
Marco wants to take a taxi cab ride if the cost to ride is 7.00 with the cost per m is 0.25 per mile and mr. o can only spend 30
77julia77 [94]

Each ride has a fixed cost of 7 and a cost that increases proportionally to the distance travelled of 0.25 per mile. Therefore the total cost of the ride is:

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We can solve the linear equation by isolating the "x" variable on the left side.

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6 0
1 year ago
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zaharov [31]

Answer:

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I hope im right!!

5 0
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