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Svetach [21]
3 years ago
6

Which of the following is the general term for the sequence m, -m, m, -m, . . .?

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0

Answer:

  A. m(-1)^(n-1)

Step-by-step explanation:

The degree of m doesn't change so none of the expressions with n as an exponent of m can possibly be correct. That leaves only choice A.

_____

You will find that when alternating signs are required, the term (-1)^n will be a factor. An offset of ±1 can be added to the n to make the initial sign be what you want. Here we want +1 for n=1, so an exponent of (n-1) is appropriate.

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Answer:

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Domain x belongs to [-4 , 0]

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M is the midpoint of AN, A has coordinates
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Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

8 0
3 years ago
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