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fomenos
3 years ago
6

How many atoms are in 3.5 moles of arsenic atoms?

Chemistry
2 answers:
crimeas [40]3 years ago
8 0

Answer:

2.1 x 1024 atoms

Explanation:

This is the right, trust me :)

solmaris [256]3 years ago
5 0

Answer:

2.107×10²⁴

Explanation:

no of moles=no of particles/Avogadro's number

3.5=X/6.02×10²³

by cross multiplication

3.5×6.02×10²³

=2.107 ×10²⁴

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Bas_tet [7]

Answer:

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Explanation:

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3 years ago
Which of the following tools is not used for measurement?
Verdich [7]

Answer:

tape measure

Explanation:

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8 0
2 years ago
The concentration of urea in a solution prepared by dissolving 16 g of urea in 20 g of H2OH2O is ________% by mass. The molar ma
Arada [10]

Answer:

44

Explanation:

Given that :

Mass of solute = Mass of urea = 16g

Mass of water = 20g

Mass of solution = (mass of solute + mass of solvent) = (mass of urea + mass of water) = (16g + 20g) = 36g

Percentage Mass = (mass of solute / mass of solution) * 100%

Percentage Mass = (16 / 36) * 100%

Percentage Mass = 0.4444444 x 100%

Percentage Mass = 44.44%

Percentage Mass = 44%

4 0
2 years ago
For the following reaction, 4.07 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 10.4 grams of
torisob [31]

Answer:

Theoretical yield = 13.7 g

% yield =76 %

Explanation:

For Al_2O_3

Mass of Al_2O_3  = 4.07 g

Molar mass of Al_2O_3  = 101.96 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{4.07\ g}{101.96\ g/mol}

Moles\ of\ Al_2O_3= 0.0399\ mol

According to the reaction:

Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O

1 mole of Al_2O_3  on reaction produces 1 mole of Al_2(SO_4)_3

So,  

0.0399 mole of Al_2O_3  on reaction produces 0.0399 mole of Al_2(SO_4)_3

Moles of Al_2(SO_4)_3  obtained = 0.0399 mole

Molar mass of Al_2(SO_4)_3 = 342.2 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0399= \frac{Mass}{342.2\ g/mol}

Mass= 13.7\ g

<u>Theoretical yield = 13.7 g</u>

The expression for the calculation of the percentage yield for a chemical reaction is shown below as:-

\%\ yield =\frac {Experimental\ yield}{Theoretical\ yield}\times 100

Given , Values from the question:-

Theoretical yield = 13.7 g

Experimental yield = 10.4 g

Applying the values in the above expression as:-

\%\ yield =\frac{10.4}{13.7}\times 100

<u>% yield =76 %</u>

6 0
2 years ago
A reaction between 46 grams of sodium and 71 grams of chlorine formed table salt and heat.
vazorg [7]

Answer:

d. 117 grams

Explanation:

The mass of the table salt produced will be 117 grams.

Chemical reactions obey the law of conservation of mass. In this regard, matter is neither created nor destroyed in the course of a chemical reaction. It is expected that the mass of the reactants and products remain the same.

 The reaction expression:

         2Na + Cl₂  →   2NaCl

So, mass of sodium  = 46g

      mass of chlorine formed = 71g

Mass of NaCl  = 46 + 71 = 117g

7 0
3 years ago
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