40.32 kg NaHCO3
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When 0.34 of HNO₃ is titrated to equivalence using 0.14 l of 0.1 m NaOH then the concentration of HNO₃ is 0.041 M
The reaction of neutralization of HNO₃ with NaOH is
HNO₃ + NaOH → H₂O + NaNo₃
When 1 mole of HNO₃ react with 1 mole of NaOH, based on chemical rection the moles of NaOH at equivalence point are equal to moles of HNO₃ present in solution: -
With the mole and volumes, we can find molarity as follows:
Moles of NaOH = moles HNO₃
⁼ 0.14 L X (0.1 mol NaOH/L) = 0.014 mole NaOH
=0.014 mol HNO₃
Molarity: -
= 0.041 M
Thus, from above solution we concluded that the concentration of HNO₃ solution is 0.041 M.
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Taking into account the definition of calorimetry, the mass of the sample is 478.41 grams.
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
- Q= -543 J because the energy is releases
- c= 0.227
- m= ?
- ΔT= Tfinal - Tinitial= 10 C - 15 C= -5 C
Replacing:
-543 J= 0.227 × m× (-5 C)
Solving:
<u><em>m=478.41 grams</em></u>
In summary, the mass of the sample is 478.41 grams.
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