<span>(1) 2x + y = 9
</span><span>(2) 8x – 2y = 6
</span>
You can eliminate the x or the y. I am going to eliminate the y
First multiply the first equation 2x + y = 9 by 2.
2x + y = 9
2(2x + y = 9)
4x +2y = 18
Now we have a new equation that we can use and we can eliminate the y from the other equation because +2y - 2y = 0. Lets do that now and solve for x.
4x +2y = 18
8x – 2y = 6
12x = 24
12x / 12 = 24 / 12
x = 2
So we found the value of x, which is 2. To find y, insert 2 into one of the original equations. I am going to use 2x + y = 9
2x + y = 9
2(2) + y = 9
4 + y = 9
-4 + 4 + y = 9 - 4
y = 9 - 4
y = 5
y = 5.
Our point is at (x, y) = (2,5)
x = 2
y = 5
Oh! I answered this question last week! Don't know if it was the same exact one, but whatever. So first cut the number of pages in Kate's report in half, then add 5 to that. So, (14÷2)+5
For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s
Answer:
Step-by-step explanation:
<u>The equation of the circle:</u>
The center is (h, k)
<u>Wen the center is the origin we have, h = 0, k = 0:</u>
The only equation in same format is the first one
Answer:
3 units right and 1 unit up.
