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photoshop1234 [79]
3 years ago
12

How many moles of atoms are in 2.00 g of 13c?

Chemistry
2 answers:
Whitepunk [10]3 years ago
4 0

There are 0.154 moles of atoms in 2.00 g of carbon-13.

<h2>Further Explanation: </h2><h3>Moles, Atomic mass and Molecular mass  </h3>
  • 1 mole of a pure substance contains a mass that is equal to the relative atomic mass or molecular mass of the substance.
  • Therefore; molar mass is given as grams per mole of a substance  

Hence;

Molar mass = mass of a substance/ Number of moles  

     g/mol = g /mole  

Thus;

  • M = m/n; where M is the molar mass, m is the mass and n is the number of moles
  • From this relationship we can therefore, calculate mass by multiplying the number of moles by molar mass of a substance.

That is; Mass = moles x molar mass  

  • To calculate number of moles;

We have; n = m/M

Number of moles = Mass of the substance/ Molar mass

  • In our case;

Mass = 2 g of Carbon-13  

Molar mass = 13.0 g/mol  

Since; Number of moles = Mass/ molar mass

Thus;

Moles = (2.0 g)/ (13.0 g/mol)

          = 0.154 moles  

Keywords: Moles, Molecular mass, relative atomic mass  

<h3>Learn more about: </h3>
  • Relative atomic mass: brainly.com/question/11096711
  • Moles calculation: brainly.com/question/9709257
  • Molar mass: brainly.com/question/8992028

Level: High school  

Subject: Chemistry  

Topic: Moles  

Sub-topic: Moles, molecular mass and mass of a pure substance.

Troyanec [42]3 years ago
3 0
I think what '13C' means is the isotope of carbon with mass number of 13. Its mass is 13 amu. The unit amu is equivalent to g/mol. The average atomic mass of Carbon is actually 12. But since we are solving for this particular isotope, we use a molar mass of 13 g/mol.

2 g C-13 * 1 mol/13 g = 0.154 moles of C-13
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A 508-g sample of sodium bicarbonate (NaHCO3) contains how many moles of sodium bicarbonate (NaHCO3)?
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//

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There are 6.0 moles of sodium bicarbonate

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2 years ago
if the mass of 191 grams NaCl reacted with 74 frams of calcium hydroxide and 80 grams of sodium hydroxide is produced, what mass
nadya68 [22]
<h3>Answer:</h3>

110.98 g/mol

<h3>Explanation:</h3>

The reaction between NaCl and Ca(OH)₂ is given by the equation;

2NaCl(aq) + Ca(OH)₂(s) → 2NaOH(aq) + CaCl₂(aq)

We are required to determine the mass of CaCl₂ produced,

We will use the following simple steps;

Step 1: Moles of NaCl and Ca(OH)₂ given

Number of moles = Mass ÷ Molar mass

Moles of NaCl

Mass of NaCl = 191 g

Molar mass NaCl = 58.44 g/mol

Number of moles = 191 g ÷ 58.44 g/mol

                             = 3.268 moles

                             = 3.27 Moles

Moles of Ca(OH)₂

Mass of Ca(OH)₂ = 74 g

Molar mass of Ca(OH)₂ = 74.093 g/mol

Number of moles = 74 g ÷ 74.093 g/mol

                             = 0.998 mole

                              = 1.0 mole

However, from the equation  2 moles of NaCl requires 1 mole of Ca(OH)₂

Therefore, from the amount of reactants available NaCl was in excess and Ca(OH)₂ is the limiting reactant .

Step 2: Moles of CaCl₂ produced

From the equation

1 mole of Ca(OH)₂ reacts with NaCl to produce 1 mole of CaCl₂

Therefore; the mole ratio of Ca(OH)₂ to CaCl₂ is 1: 1

Thus;

Moles of CaCl₂ produced is 1.0 moles

Step 3: Mass of CaCl₂ produced

Moles of CaCl₂ = 1.0 mole

Molar mass CaCl₂ = 110.98 g/mol

But; mass = number of moles × Molar mass

Therefore;

Mass of CaCl₂ = 1.0 mole × 110.98 g/mol

                       = 110.98 g CaCl₂

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3 years ago
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