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DaniilM [7]
2 years ago
14

if 12 molecules of methane reacted with plenty of oxygen, we should expect to produce____ molecules of car on dioxide and _____

molecules of water
Chemistry
1 answer:
ziro4ka [17]2 years ago
5 0

Answer:

12 molecules of carbon dioxide

24 molecules of water

Explanation:

Given parameters:

Number of molecules of methane = 12 molecules

Unknown:

Number of molecules of carbon dioxide = ?

Number of molecules of water = ?

Solution:

The given amount of methane is the limiting reagent in this reaction. By this, we can ascertain the amount of products that will be formed and the extent of the reaction.

We first write the balanced chemical equation for this reaction;

             CH₄     +    2O₂    →     CO₂   +     2H₂O

From balanced equation;

                 1 mole of methane produced 1 mole of carbon dioxide

  12 molecules of methane will produce 12 molecules of carbon dioxide

Also;

             1 mole of methane produced 2 moles of water;

12 molecules of methane will produce (12 x 2)molecules = 24 molecules of water

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How many moles are there in 67.2 grams of h2
yarga [219]

Answer: 33.3 moles

Explanation: 67.2 g H2 = 67.2/2.016 = 33.3 moles

7 0
3 years ago
If we mix 25 grans if sodium oxide with a large amount of potassium chloride, how many grams of sodium chloride should be produc
amid [387]

Answer:

47.2 g

Explanation:

Data given:

mass of Sodium oxide (Na₂O) = 25 grams

mass of potassium chloride (KCl) = excess

amount of sodium chloride (NaCl) = ?

Solution:

First we look for reaction of sodium oxide with potassium chloride.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

As we know that potassium chloride is in excess amount and sodium oxide is 25 g so it means sodium oxide is a limiting reactant and amount of sodium chloride depends on the amount of sodium oxide.

So, now we will look for mole mole ration of Na₂O to NaCl.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

                    1 mol                              2 mol

from above equation we come to know that 1 mole of Na₂O gives 2 moles of NaCl.

Now convert moles to mass

As we Know

Molar mass of Na₂O = 2(23) + 16 = 62 g/mol

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

So

                  Na₂O              +   2 KCl    ----------->      2 NaCl          +      K₂O

             1 mol (62 g/mol)                                   2 mol (58.5 g/mol)

                  62 g                                                          117 g

So, it means that 62 g of Na₂O produce 117 g of NaCl then how many grams of NaCl will be produce by 25 g of Na₂O

Apply unity formula

                           62 g of Na₂O ≅ 117 g of NaCl

                           25 g of Na₂O ≅ X g of NaCl

Do cross multiplication

                          X g of NaCl = 117 g x 25 g / 62 g

                          X g of NaCl = 47.2 g

So,

25 g of Na₂O gives 47.2 grams of NaCl.

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