<span>Molds are created to achieve a
specific design of a material. These materials either came from a process of
having a higher or lower temperature. Therefore, the molder must have thermal
resistant properties. Low melting points means that the material to be shaped
came from a cooler process. Wood and metal have higher thermal conductivity and
therefore can easily be cooled. The wax can turn really hard and can be
unbreakable when present in colder materials due to the lipids present in it. Clay
however can become a mold because of its low melting point.</span>
100 square each for newtons of force
Answer:
Ethyl methyl ether.
Explanation:
- The mono ether is named commonly by <em>dividing the molecule into two parts, writing them in alphabetical order, and adding ether in the end of the name.</em>
- In this compound; we have two parts CH₃ (methyl) and CH₃CH₂ (ethyl).
So, it is named ethyl methyl ether.
- The IUPAC name of this name is Methoxyethane.
Answer:
The pH at the midpoint in the titration of an acid with a base is
A) equal to the pK of the corresponding base.
B) equal to the pK of the corresponding acid.
C) equal to 14 minus the pK of the corresponding acid.
D) equal to 14 plus the pK of the corresponding base.
E) none of the above
Explanation:
When a weak acid is titrated with a strong base, then a buffer solution is formed.
pH of a buffer solution can be calculated by using the formula:
![pH=pKa+log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
Exactly at the mid point,
[conjugate base of the salt]=[acid]
So, log [salt]/[acid] =0
Hence, pH of the solution will be equal to pKa of the weak acid.
Answer is option B.
Answer:
Cobalt (III) Iodide
General Formulas and Concepts:
<u>Chemistry - Compounds</u>
- Reading a Periodic Table
- Writing Compounds
- Naming Compounds
Explanation:
<u>Step 1: Define</u>
CoI₃
<u>Step 2: Identify</u>
Co is a Transition Metal, has either a charge of 2+ or 3+
I is a Halogen, has a charge of 1-
<u>Step 3: Write name</u>
We need to balance the charges, and in order to do that, we must have a Co³⁺
Cobalt (III) Iodide
