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gtnhenbr [62]
3 years ago
11

The complex number _______ lies in the shaded area of the graph. The complex number _______ does not lie in the shaded area.

Mathematics
1 answer:
Anastaziya [24]3 years ago
5 0
Think of imaginary numbers on a complex plane as coordinates - take the real part, that's the x coordinate, the imaginary part that's the y coordinate.

Therefore, for the first blank, -1+3i lies in the shaded area, because its coordinates are (-1,3).
And following on from that for the second one, -4i does not lie in the shaded area, since its coordinates are (0,-4).

Tl;dr is taking a complex number a+bi and placing it on a complex plane, it will have coordinates (a,b)
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use each of the digits 2,3,5,8 once with any combination of +,-,., or () to write an expression with a value of 104
densk [106]
8 times 13 = 104

8 * ( 5*3 - 2) = 104
4 0
2 years ago
Find an m > 0 such that the the equation x^4−(3m+2)x^2+m^2=0 has four real solutions that form an arithmetic sequence.
Aleonysh [2.5K]

Answer:

The value of m is 6.

Step-by-step explanation:

Here, the given equation,

x^4-(3m+2)x^2+m^2=0

x^4+0x^3-(3m+2)x^2+0x+m^2=0

Let the roots of the equation are a-3b, a-b, a+b and a + 3b, ( they must be form an AP )

Thus, we can write,

a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}

=\frac{0}{1}=0

\implies a=0----(1)

(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}

=\frac{-3m-2}{1}

3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2

-10b^2=-3m-2

\implies b^2=\frac{3m+2}{10}-----(2)

(-3b)(-b)(b)(3b)=\frac{\text{Constant term}}{\text{coefficient of}x^4}= m^2

9b^4=m^2

9(\frac{3m+2}{10})^2=m^2

9(\frac{9m^2+4+12m}{100})=m^2

81m^2+36+108m=100m^2

-19m^2+108m+36=0

19m^2-108m-36=0

19m^2-114m+6m-36=0

19m(m-6)+6(m-6)=0

(19m+6)(m-6)=0

\implies m=-\frac{6}{19}\text{ or }m=6

But m > 0,

Hence, the value of m is 6.

4 0
3 years ago
I NEED HELP FOR THIS QUESTION PLSSS
defon
Answer: 132 degrees
5 0
3 years ago
Read 2 more answers
Help me please!!!!!!!!!!!!
iVinArrow [24]

Answer: 0.25g<2.50.... g<10

Step-by-step explanation: Let us say that the number of gumballs bought is represented by the variable g. In this case, the question is asking how many gumballs can be bought without surpassing the price of $2.50. We know that each gumball is $0.25, therefore the number of gumballs we buy times $0.25 has to be less than $2.50. Hence, the inequality would be 0.25g<2.50. If we were to solve this then g<2.50/0.25-----> g<10. In conclusion, the number of gumballs you can buy has to be less than 10. Thank you!

6 0
3 years ago
8 degrees and 90 minutes
cestrela7 [59]

Answer:

3. 8 degrees/90 minutes

4. 200 miles/3 hours

5. $6/5 pickles

3 0
2 years ago
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