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3 years ago

I need Help!!!!!! Correct answers gets 10 Points.

Mathematics

2 answers:

neonofarm [45]3 years ago

5 0

a. Using point C as a center of rotation, rotate the figure 90 degrees counterclockwise. Then, translate the figure 4 units down.

ser-zykov [4K]3 years ago

3 0

First an anticlockwise rotation about the origin of 90 degrees

Then a translation of 2 units to the right,

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after a party, there are parts of three pizzas remaining. There is a 1/5 of a pepperoni pizza remaining, 3/8 of a cheese pizza r

Alona [7]

Answer:

2/5

Step-by-step explanation:

Multiply all the fraction

8 0

3 years ago

What’s the ratio of the area?<br> 250/686<br> 25/49<br> 5/7<br> 125/343

earnstyle [38]

Answer:

Your answer is 25:49

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Hope it helps...

Have a great day!!

4 0

3 years ago

Need help please thx you

erma4kov [3.2K]

$72.

20% of 60 is 12

$12 + $60 = $72

6 0

3 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

3 years ago

Katrinas bank statements shows a closing balance of 172.62 they are no outstanding checks or deposit her checkbook hows a balanc

Maslowich

Some how Katrina has forgotten to write a check amount down in here check book. to find out the amount you would subtract 190.62 from 172.62

5 0

3 years ago

Read 2 more answers