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mamaluj [8]
3 years ago
12

Select all the triangles that would have an area of 16 square inches. Answer Choices A triangle with a base length of 8 in. and

a height of 2 in. A triangle with a base length of 4 in. and a height of 8 in. A triangle with a base length of 2 in. and a height of 16 in. A triangle with a base length of 4 in. and a height of 4 in.
Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0
A triangle with a base of length 4 in. and a height of 8 in.
A triangle with a base of 2 in. and a height of 16 in.
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2/10 + 7 = 10<br> two over 10 plus 7 equals 10<br> pls help me solve the enquality
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Evaluate the integral Integral ∫ from (1,2,3 ) to (5, 7,-2 ) y dx + x dy + 4 dz by finding parametric equations for the line seg
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\vec F(x,y,z)=y\,\vec\imath+x\,\vec\jmath+3\,\vec k

is conservative if there is a scalar function f(x,y,z) such that \nabla f=\vec F. This would require

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\dfrac{\partial f}{\partial y}=x

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(or perhaps the last partial derivative should be 4 to match up with the integral?)

From these equations we find

f(x,y,z)=xy+g(y,z)

\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

f(x,y,z)=xy+h(z)

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\displaystyle\int_{(1,2,3)}^{(5,7,-2)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz=\int_{(1,2,3)}^{(5,7,-2)}\nabla f(x,y,z)\cdot\mathrm d\vec r

=f(5,7,-2)-f(1,2,3)=\boxed{18}

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