All categories

3 years ago

What is the axis of symmsymmiof y=2(x+1)^2

Mathematics

1 answer:

My name is Ann [436]3 years ago

6 0

Y=a(x-h)^2+k
axis of symmetry is x=h

given
y=2(x-(-1)^2+0
h=-1
axis of symmetry is x=-1

You might be interested in

Select all the expressions that are equivalent to .

olga55 [171]

Answer:

1. 9 - 10n = -1 + 1/10

2. 14 - 3n = 14 - 3n

3.14 - 21 = - 7⋅ (3n - 2)

4. (2-3n)⋅7 = Sorry i dont know

5. I HAVE NO IDEA SO SORRY

Step-by-step explanation:

5 0

3 years ago

Amanda buys four tickets to the baseball game for $24 each which equation shows the closest estimate of the total amount of Aman

Alik [6]

Answer:

I think $800

Step-by-step

round 24 down to 20

and multiply it by 4

I got 800

24 ->20

20x4=800

3 0

3 years ago

Read 2 more answers

Which equation is the inverse of y = 9x2 - 4?

m_a_m_a [10]

Answer:

The inverse will be:

$y' = \frac{\sqrt{x+4}}{3}$

Step-by-step explanation:

In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :

$f(x) = 9x^{2} - 4$

$y = 9x^{2} - 4$

$x = 9y' ^{2} - 4$

Now solve for y'.

First add 4 in both sides of the equation and change to the left y'.

$x + 4= 9y'^{2} - 4+4$

$9y'^{2}$ = x + 4

Second divide by 9

$9y'^{2}$ /9 = (x + 4)/9

$y'^{2}$ = (x + 4)/9

Now you will have to clear y, with the square root.

$[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}$ [/tex] =

Simplifying terms

$y' = \frac{\sqrt{x+4}}{3}$

$f^{-1}(x) = \frac{\sqrt{x+4}}{3}$

You can check the answer by doing the evaluation of the following equation:

(f o $f^{-1}$ ) (x)

substitute the equation for y' or inverse function $f^{-1}$

f( $\frac{\sqrt{x+4} }{3}$ )

Now substitue the value into f(x)

You will have

$= 9(\frac{\sqrt{x+4} }{3}} )^{2} - 4\\\\Solving\\\\9(\frac{{x+4} }{9}} ) - 4$

5 0

3 years ago

The first term in a geometric series is 64 and the common ratio is 0.75. Find the sum of the first 4 terms in the series.

maks197457 [2]

Answer:

195.25

Step-by-step explanation:

Consider geometric series S(n) where initial term is a

So S(n)=a+ar^1+...ar^n

Factor out a

S(n)=a(1+r+r^2...+r^n)

Multiply by r

S(n)r=a(r+r^2+r^3...+r^n+r^n+1)

Subtract S(n) from S(n)r

Note that only 1 and rn^1 remain.

S(n)r-S(n)=a(r^n+1 -1)

Factor out S(n)

S(n)(r-1)=a(r^n+1 -1)

The formula now shows S(n)=a(r^n+1 -1)/(r-1)

Now use the formula for the problem

4 0

3 years ago

I need help with number 30......……

goblinko [34]

65+56=121, 180-121=59, 59/8=7.375 , so the answer is A

4 0

4 years ago