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2 years ago

What is the axis of symmsymmiof y=2(x+1)^2

Mathematics

1 answer:

My name is Ann [436]2 years ago

6 0

Y=a(x-h)^2+k
axis of symmetry is x=h

given
y=2(x-(-1)^2+0
h=-1
axis of symmetry is x=-1

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Mike and Kate plan to save money for their wedding over a 20 month period. They will need to save $8,000 to help pay for the wed

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Step-by-step explanation:

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3 years ago

When given a graph, the vertical line test can be used to determine functionality. Describe the vertical line test and explain t

diamong [38]

Answer:

The vertical line test is a way for you to see if a graph represents a function. It allows you to identify if any x values have more than one y value.

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3 years ago

Read 2 more answers

What is the research hypothesis when using anova procedures?

Pachacha [2.7K]

When using ANOVA procedures, the research hypothesis is: there is no significance difference within the mean values of the groups.

<h3>What is a Research Hypothesis in ANOVA Procedure?</h3>

ANOVA procedure compares the mean values of different groups that are administered with treatments. The research hypothesis, such as the null hypothesis would be stated as: no significance difference in the mean values within the groups.

Thus, we can conclude that the research hypothesis when using the ANOVA procedures can be stated as a null hypothesis, which states that: there is no significance difference within the mean values of the groups.

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2 years ago

Factor out the coefficient of the variable term The expression 1/10k-7/10 factored is

Goshia [24]

Answer:

The answer: 1/10x (k-7)

Step-by-step explanation:

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3 years ago

Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74

lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0

3 years ago