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Aloiza [94]
2 years ago
8

The area of a circle is

="144\pi \: {m}^{2} " alt="144\pi \: {m}^{2} " align="absmiddle" class="latex-formula">
What is the diameter of the circle? ​
Mathematics
1 answer:
DiKsa [7]2 years ago
5 0

Answer:

24

Step-by-step explanation:

The area is calculated by multplying radius (half of diameter) by itself and then with number pi

the area for this circle is given as

144π m^2

144 is the squared form of 12 if the radius is 12 the diameter is 24

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∫dx/(x+√(x^{2} +x+1)
DIA [1.3K]

Answer:

es1433

Step-by-step explanation:

8 0
2 years ago
20 is 25% of what number
borishaifa [10]
Hey there! :D

If 20 is 25% of a number, 

we know that it is a quarter of a number. 

20*4= 80

20 is 25% of 80.

I hope this helps!
~kaikers
5 0
3 years ago
Read 2 more answers
Choose the graph that represents the following system of inequalities: y ≤ −3x + 1 y ≤ 1 over 2x + 3 In each graph, the area for
Vanyuwa [196]

The graph that represents the inequality has been shown in the attachment.

<h3>How to solve for the graph</h3>

We have these equations

y ≤ −3x + 1

y ≤ x + 3

We remove the inequality sign from both of these equations

y = −3x + 1

y = x + 3

−3x + 1  = x + 3

such that

x = -0.5

we use this value for x in any of the equations

x + 3 = -0.5 + 3

= 2.5

the point of intersection is at 2.5, -0.5

we test for the origin. 0,0

3x + 1

= 3*0 + 1

= 1

for  x + 3

0+3 = 3

This is 0≤1 and 0≤3

Hence the graph should be shaded to the origin.

Read more on a graph here: brainly.com/question/14030149

#SPJ1

7 0
1 year ago
Marge cut 16 pieces of tape for mounting pictures on poster board. Each piece of tape was 3/8 inch long. How much tape did Marge
mafiozo [28]
Hi! :)

It sounds like you need to multiply this fraction. 

\frac{3}{8}*16=6

So, Marge used 6 total inches of tape. 

Hope this helps!
5 0
3 years ago
HELPP!!
SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0
3 years ago
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