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4 years ago

Which statement is true about the ranges for the box plots?

Mathematics

2 answers:

11111nata11111 [884]4 years ago

9 0

Answer:

Step-by-step explanation:

Range of a box plot is the highest value minus the lowest value.

The picture attached shows which one is the highest value and which one is the lowest value.

From our understanding and given graphs:

The first Box Plot's Highest Value is 15 and Lowest Value is 3.

Range = Highest - Lowest = 15 - 3 = 12

The second Box Plot's Highest Value is 16 and Lowest Value is 4.

Range = Highest - Lowest = 16 - 4 = 12

Thus, the range of both the box plots are same. Answer choice A is right.

erastova [34]4 years ago

8 0

A. The range of the Morning box plot is the same as the range of the Afternoon box plot.

Subtract the minimum from the maximum and your answer for both box plots will be 12. So the range is the same for the Afternoon and Morning Box Plots. Hope this helps :)

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Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

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The left-hand limit

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The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

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3 years ago

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Answer:

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Step-by-step explanation:

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They numbers 2,5 or ___ are numbers that would make 34,? 21 divisible by 3.

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Answer:

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Step-by-step explanation:

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