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4 years ago

Which statement is true about the ranges for the box plots?

Mathematics

2 answers:

11111nata11111 [884]4 years ago

9 0

Answer:

Step-by-step explanation:

Range of a box plot is the highest value minus the lowest value.

The picture attached shows which one is the highest value and which one is the lowest value.

From our understanding and given graphs:

The first Box Plot's Highest Value is 15 and Lowest Value is 3.

Range = Highest - Lowest = 15 - 3 = 12

The second Box Plot's Highest Value is 16 and Lowest Value is 4.

Range = Highest - Lowest = 16 - 4 = 12

Thus, the range of both the box plots are same. Answer choice A is right.

erastova [34]4 years ago

8 0

A. The range of the Morning box plot is the same as the range of the Afternoon box plot.

Subtract the minimum from the maximum and your answer for both box plots will be 12. So the range is the same for the Afternoon and Morning Box Plots. Hope this helps :)

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Step-by-step explanation:

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3 years ago

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3 years ago

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4 years ago

A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an

liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

when the angle is 30 degrees

$tan(30) = \frac{6000}{d1}$

$d1 = \frac{6000}{tan(30)}$

$d1 = \frac{6000}{0.577}$

d1 = 10392.3 meters

when the angle is 60 degrees

$tan(60) = \frac{6000}{d2}$

$d2 = \frac{6000}{tan(60)}$

$d2 = \frac{6000}{1.732}\\$

d2 = 3464.1 meters

distance travelled by aircraft in 1 min is

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

Now converting to m/sec

=> $\frac{6928.2}{60}$

=>115.47 m/sec

4 0

3 years ago