Answer:
1. (4,1,2,3,5)
Step-by-step explanation:
Since all the members of set A are present in "1"
The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Translate it 8units to the right then reflect it over the line y=-3
Why?
- We can see the Quadrilateral is in Quadrant 3.
- If we translate it by 8units right it come to Quadrant 4.
- Now reflect it over line y=-3
- we will get Quadrilateral 2
Answer:
87/9
Step-by-step explanation:
Answer:
I honestly dont know I just need the points