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In-s [12.5K]
3 years ago
6

Help me pleaseeee!!!!!!

Mathematics
1 answer:
lilavasa [31]3 years ago
7 0
The formula for finding the perimeter of any rectangle is 2(width + length).
a) width= x ; length= x+7. Plug them into the formula 2( x+x+7). Combine like terms inside the parenthesis: 2(2x+7). Distributive property: 4x+14 is your answer.

b) Width=y ; length: 2y-1. Plug them into the formula: 2(y+2y-1). Combine like terms inside the parenthesis: 2(3y-1). Distributive property: 6y-2, is your answer.

I'm only doing the first two, the rest you should be able to do them. 
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Given the function: j(x)=x^2+3x-4 ... Match the description with the critical point.
Assoli18 [71]

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1

Step-by-step explanation:

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Simplify (7x) - (-2x).<br> O 5x<br> 0 -5x<br> O 9x<br> 0-9x<br> NEXT QUESTION<br> 2<br> ASK FOR UEL
marysya [2.9K]

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Step-by-step explanation:

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4 years ago
What is |Ay| in the system of linear equations below?<br> -8x+y=6<br> 3x-2y=-1
Nataliya [291]

A=\left[\begin{array}{ccc}-8&1\\3&-2\end{array}\right]\\\\|A_y|=\left|\begin{array}{ccc}-8&6\\3&-1\end{array}\right|=(-8)(-1)-(3)(6)=8-18=-10

6 0
3 years ago
Read 2 more answers
MATRECIES: Suppose ={u,v,w}⊆R3 is linearly independent. Determine if the set 4 ={u, v, v−w, u+v+w} is linearly independent or li
AlladinOne [14]

The set is linearly dependent.

To explicitly prove this, we need to show there is at least one choice of constants c_1,c_2,c_3,c_3\in\Bbb R such that

c_1 u + c_2 v + c_3(v-w) + c_4(u+v+w) = 0

or equivalently,

(c_1 + c_4) u + (c_2 + c_3 + c_4) v + (-c_3 + c_4) w = 0

which is the same as solving the system of equations

\begin{cases} c_1 + c_4 = 0 \\ c_2 + c_3 + c_4 = 0 \\ -c_3 + c_4 = 0 \end{cases}

From the first and last equations, we have c_1=-c_4 and c_3=c_4. Substituting these into the second equation leaves us with c_2-2c_1=0, and so the overall solution set is

c_1 = \dfrac12 c_2 = -c_3 = -c_4

for which there are infinitely many not-all-zero solutions.

3 0
2 years ago
I need help on how to do this
REY [17]
Sorry idk how to do that either
8 0
3 years ago
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