Question

What is |Ay| in the system of linear equations below? -8x+y=6 3x-2y=-1

Answer 1

$A=\left[\begin{array}{ccc}-8&1\\3&-2\end{array}\right]\\\\|A_y|=\left|\begin{array}{ccc}-8&6\\3&-1\end{array}\right|=(-8)(-1)-(3)(6)=8-18=-10$

Answer 2

Answer:

|Ay| = - 10

y = 10/19

x = 2 - 10/57

Step-by-step explanation:

we have to set the data into array format to be able to solve the problem.

$A=\left[\begin{array}{ccc}-8&1\\3&-2\end{array}\right]\\\\|A_y|=\left|\begin{array}{ccc}-8&6\\3&-1\end{array}\right|=(-8)(-1)-(3)(6)=8-18=-10$

but then to calculate for the values of x and y we solve simultaneously

-24x + 3y = 18

-24x - 16y = 8

19y =10

y = 10/19

substituting the value of y

3x + 10/19 = 6

3x = 6-10/19

x = 2 - 10/57