Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.
Answer:
The answer would be 8.1
Step-by-step explanation:
For the smaller triangle, you use the pythagorean theorem. a squared + b squared = c squared.
To find one of the legs, you do 5 squared - 3 squared = b squared.
25 - 9 = b squared. (BD)
16 = b squared
4 = b
Now for the bigger right triangle. You still use the same tactic.
7 squared + 4 squared = c squared (which is AB)
49 + 16 = c squared
65 = c squared
That means c would equal: square root of 65, which is 8.0622577483 which rounds to 8.1
Subtract the known trinomial from the total sum:
6x2 - 5x + 4 - 4x2 + 3x - 2 = 2X^2 -8x +6
I hope this helps :)
They live 9 3/4 blocks away from eachother
= 0.02 is the answer