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Ugo [173]
3 years ago
15

At the middle school graduation dance, the DJ played 12 slow dances, which was equal to the quotient of the number of fast dance

s and two.
Mathematics
1 answer:
belka [17]3 years ago
3 0

quotient means divide

 so 12 = x/2

x = 12*2 = 24

 x =24 fast songs

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Jim weighs 30 pounds less than Tom, and together they weigh 210 pounds. Let n = Tom's weight in pounds.
zlopas [31]

The equation that represents the given problem is (n-30) + n = 210. The correct option is the first option (n-30) + n = 210

<h3>Linear equation</h3>

From the question, we are to write an equation for the given problem

From the given information,

n = Tom's weight in pounds

If Jim weighs 30 pounds less than Tom

Then,

Jim weighs (n - 30)

Thus,

The sum of their weight is

(n-30) + n

∴ (n-30) + n = 210

Hence, the equation that represents the given problem is (n-30) + n = 210. The correct option is the first option (n-30) + n = 210

Learn more on Linear equations here: brainly.com/question/4681624

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Varvara68 [4.7K]

Answer:

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Step-by-step explanation:

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3 years ago
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The permitir of the garden is (6x+2) units. Find the length of the missing side .
Snezhnost [94]

Answer: ? = x + 1


Step-by-step explanation:

The perimeter of the garden is x + 3x + 1 + x + ?

The perimeter of the garden is also (6x + 2)

Therfore:

x + 3x + 1 + x + ? = 6x + 2

<em>Collect like terms: </em>

5x + 1 + ? = 6x + 2

<em>Subtract 5x from both sides:</em>

1 + ? = x + 2

<em>Subtract 1 from both sides:</em>

? = x + 1

You cannot find ? as a number, only in terms of x.

5 0
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Find the greatest common factor of 636363 and 424242.
astra-53 [7]

Answer:

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Step-by-step explanation:

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6 0
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Which line(s) intersect the parabola y = x^2 − 3x + 4 at two points? Select all that apply. A. y = –3x + 2 B. y = –3x + 3 C. y =
TEA [102]

Answer:

C and D

Step-by-step explanation:

Equating the line A and the parabola, we get

-3x + 2 = x² - 3x + 4

0 = x² - 3x + 4 +3x - 2

0 = x² + 2

-2 = x²

which has no real solutions. Then, the line A and the parabola don't intersect each other.

Equating the line B and the parabola, we get

-3x + 3 = x² - 3x + 4

0 = x² - 3x + 4 + 3x - 3

0 = x² + 1

-1 = x²

which has no real solutions. Then, the line B and the parabola don't intersect each other.

Equating the line C and the parabola, we get

-3x + 5 = x² - 3x + 4

0 = x² - 3x + 4  + 3x - 5

0 = x² - 1

1 = x²

√1 = x

which has 2 solutions, x = 1 and x = -1. Then, the line C and the parabola intersect each other.

Equating the line D and the parabola, we get

-3x + 6 = x² - 3x + 4

0 = x² - 3x + 4  + 3x - 6

0 = x² - 2

2 = x²

√2 = x

which has 2 solutions, x ≈ 1.41 and x ≈ -1.41. Then, the line D and the parabola intersect each other.

4 0
3 years ago
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