Help me plzz im almost. out of time
1 answer:
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Answer:
(a)123 km/hr
(b)39 degrees
Step-by-step explanation:
Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.
Distance = Speed X Time
Therefore: PQ =50km/hr X 2 hr =100 km
It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.
Distance, QA=50km/hr X 2.5 hr =125 km
Using alternate angles in the diagram:
(a)First, we calculate the distance traveled, PA by plane Y.
Using Cosine rule
SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am
Time taken =1.5 hour
Therefore:
Average Speed of Y
(b)Flight Direction of Y
Using Law of Sines
The direction of flight Y to the nearest degree is 39 degrees.
Add 4 to both sides to isolate the variable (-4+4=0) (2x+0=2x) (0+4=4) which leaves you with 2x=4 divide both sides by 2 to get rid of the number in front of the variable to get x by itself (2x/2=x) (4/2=2) therefore you’re left with x=2 (lo siento yo no hablo español la respuesta es x=2)
