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Jet001 [13]
3 years ago
14

Can somebody please help me either these two

Mathematics
2 answers:
Zarrin [17]3 years ago
4 0
1. 8.96 x 105 I think
2. <span>4.25 x 10-4
</span>
pochemuha3 years ago
4 0
Problem 1.

9.3 * 10^7 - 3.4 * 10^6 =

You need the same exponent:

= 9.3 * 10^7 - 0.34 * 10^7

= 8.96 * 10^7

Problem 2.

0.00045 - 2.5 * 10^(-5) =

= 45 * 10^(-5) - 2.5 * 10^(-5)

= 42.5 * 10^(-5)

= 4.25 * 10^(-4)
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what exactly am i solving for ?

Step-by-step explanation:

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Which represents a quadratic function y=2(x+2)(x-1) in standard form
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3 years ago
How do I solve this to find angle G?
VashaNatasha [74]

Answer:

Step-by-step explanation:

The angle at E is 90 degrees.

All tangents of a circle always meet the radius at a 90 degree angle.

90 + 67 + G = 180o    All triangles have 180 degrees. Combine left.

157 + G = 180o           Subtract 157 from both sides.

157 - 157 + G + 180 - 157

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5 0
3 years ago
How many different perfect cubes are among the positive actors of 2021^2021
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Answer:

hope this helps :D

Step-by-step explanation:

Perfect cube factors:

If a number is a perfect cube, then the power of the prime factors should be divisible by 3.

Example 1:Find the number of factors of293655118 that are perfect cube?

Solution: If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube 4x3x2x3=72

Perfect square and perfect cube

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.

Example 2: How many factors of 293655118 are both perfect square and perfect cube?

Solution: If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are 2x2x1x2=8

Example 3: How many factors of293655118are either perfect squares or perfect cubes but not both?

Solution:

Let A denotes set of numbers, which are perfect squares.

If a number is a perfect square, then the power of the prime factors should be divisible by 2. Hence perfect square factors must have

2(0 or 2 or 4 or 6 or 8)—– 5 factors

3(0 or 2 or 4 or 6)  —– 4 factors

5(0 or 2or 4 )——- 3 factors

11(0 or 2or 4 or6 or 8 )— 5 factors

Hence, the total number of factors which are perfect square i.e. n(A)=5x4x3x5=300

Let B denotes set of numbers, which are perfect cubes

If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube i.e. n(B)=4x3x2x3=72

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are i.e.n(A∩B)=2x2x1x2=8

We are asked to calculate which are either perfect square or perfect cubes i.e.

n(A U B )= n(A) + n(B) – n(A∩B)

=300+72 – 8

=364

Hence required number of factors is 364.

8 0
3 years ago
At midnight the temperature is -6c. At midday the temperature is 9c. By how much did the temperature rise?
Rus_ich [418]

Answer:

The temperature increased by 15 degrees 6+9=15

Step-by-step explanation:

Hope it helps

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