Answer:
Any nucleus that has an overall spin quantum number of zero (I=0) is NMR inactive
Explanation:
A wide range of nuclei are found to be NMR active. NMR is the acronym for nuclear magnetic resonance. It is a powerful spectroscopic tool which uses radio waves. The nuclear spin is described by the nuclear quantum number I and can take on values of; 0,1/2, 1, 3/2,2,5/2 etc.
Any nucleus that has an overall spin quantum number of zero (I=0) is NMR inactive e.g Carbon-12 and Oxygen-16 nuclei.
Commonly, all NMR active nuclei posses I ≥ 1/2, Hydrogen -1 , Carbon-13 and boron-11 are common examples of NMR active nuclei.
A. low blood glucose <span>is an example of a condition in which homeostasis is maintained using a negative feedback loop</span>
if O is -2 and hydrogen +1 then phosphorus is +5
What this tells you is that the oxidation number of P in phosphorus acid must be +3 or +4, while the value for phosphoric acid must be +5 or +6. Since phosphorus is a member of group 5A, it has 5 electrons in its valence shell. As a result, the most common oxidation states it can have are +3 (s2p0) or +5 (s0p0).
So far we have determined the oxidation state at P. What needs to be done now is to add as many oxygens and hydroxyl (OH) to make the molecule neutral. The correct combination will have the correct Lewis-dot structure. For phosphorous acid we need a combination that will add up to +3. This can be done by adding 3 OH- to the central atom to yield the structure H3PO3. There is a little caveat though. Because this is not a hydro___acid, it is implied that there must be at least one oxo ligand (O^2-) bonded to P. Therefore, the actual bonding structure is not P(OH)3 but rather H-P(=O)(OH)2, where one H is bonded directly to the phosphorus atom and is the least acidic of the protons. The great thing is that the oxidation charge of P is still +3 because P is slightly more electronegative than H (some theories will say otherwise); thus the hydrogen is regarded as H+ for this example.
With phosphoric acid, charge of +5, you can have 3 OH- and 1 O^2- to make a neutral molecule:
O=P(OH)3.
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Answer:
C
Explanation:
A diatomic element in that list is Bromine
