Answer:
Final temperature = 91.75 °C
Explanation:
Given data:
Mass of water = 45 g
Initial temperature = 12 °C
Energy required = 15 Kj (15000 j)
Final temperature = ?
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Solution:
Q = m.c. ΔT
15000 j = 45 g × 4.18 j/g.°C × (T2 -T1)
15000 j = 45 g × 4.18 j/g.°C × (T2- 12 °C)
15000 j = 188.1 J/°C × (T2- 12 °C)
15000 j / 188.1 J/°C = T2- 12 °C
79.745 °C = T2 - 12 °C
T2 = 79.745 °C + 12 °C
T2 = 91.75 °C
