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Nata [24]
3 years ago
14

In parallelogram LMNO, what are the values of x and y?

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
7 0
O and M are equal... N and L are equal. The whole shape adds up to 360 degrees.
3x-55=2x
x=55
So O= 110, M=110. That leaves the rest of the shape with 140. Divide by 2. N and L= 70... plug it in.
70=5y
y=14
So the answer is x=55 y=14
jeka943 years ago
6 0

Answer:

the answer x=55 y=14

Step-by-step explanation:


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C is the midpoint of chord AB and D is the midpoint of arc AB.Given that AB=36 unit and CD=6 unit then What is the radius of cir
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Can someone help me with these 2 questions real quick?
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Answer:

<M = 32 and <Y = 103

Step-by-step explanation:

1. Since triangle BCM is congruent to triangle ZYR, we know the corresponding parts of the triangles are congruent. Therefore, <Z = <B = 45. The sum of a triangle’s angles is 180, so <M = 180 - <B - <C = 180 - 45 - 103 = 32

2. This is the exact same diagram, so we can use the information we have collected in #1. Since corresponding parts of congruent triangles are congruent, <Y must be congruent to <C, which equals 103. Therefore, <Y = 103.

I hope this helps! :)

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Help pls im being timed
Nitella [24]

The trigonometric ratios show that the angle FHE is 48.59°.

<h3>RIGHT TRIANGLE</h3>

A triangle is classified as a right triangle when it presents one of your angles equal to 90º.  The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.

The Pythagorean Theorem says: (hypothenuse)^2=(leg_1)^2+(leg_2)^2. And the main trigonometric ratios are:

sin(\alpha) =\frac{opposite \;leg }{hypotenuse} \\ \\ cos(\alpha) =\frac{adjacent\;leg }{hypotenuse} \\ \\ tan(\alpha) =\frac{sin(\alpha )}{cos(\alpha )}= \frac{opposite \;leg }{adjacent\;leg } \\ \\

It is important to remember that the sum of internal angles for any triangle is 180°.

From the question, it is possible to see 2 right triangles (HGF and FHE).

You can find the hypotenuse of the triangle HGF from the  trigonometric ratio: sen Θ

sin45=\frac{opposite\; leg }{hypotenuse} =\frac{\sqrt8}{hypotenuse}\\ \\ \frac{\sqrt{2} }{2} =\frac{\sqrt{8} }{hypotenuse} \\ \\ \sqrt{2}*hypotenuse=2\sqrt{8} \\ \\ hypotenuse=\frac{2\sqrt{8} }{\sqrt{2}} =2\sqrt{4} =2*2=4

The hypotenuse of triangle HGF is one of legs for the triangle FHE. The, you can find the angle FHE from the  trigonometric ratio: tan β. Thus,

sin \beta =\frac{opposite\; leg }{adjacent\; leg} =\frac{3}{4}\\ \\ sin \beta=\frac{3}{4}=0.84806\\ \\ arcsin\beta =48.59^{\circ \:}

Learn more about trigonometric ratios here:

brainly.com/question/11967894

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2 years ago
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azamat

Answer:

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Now we just set up the equation where we have the equation whatever one side is times itself  three times, (or x cubed) it will equal 1,000,000 or x^3=1,000,000,000.  Now you just take the cube root of 1,000,000 which gets us 100.  so the length, width and height are 100 small cubes.

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