All categories

3 years ago

50 points! ASAP!

Mathematics

2 answers:

hichkok12 [17]3 years ago

8 0

First, find the volume of the pyramid on top:

(2.5 * 3 * 1.5) / 3 = 3.25

Then, find the volume of the rectangular prism:

2.5 * 3 * 2 = 15

Add the two volumes together:

3.25 + 15 = 18.25

To explain: you found the volume of each separate part and added it together.

Mademuasel [1]3 years ago

7 0

Answer:

<em>Method: First find the area of the pyramid on top, then find the area of the rectangular prism below.</em>

V of the pyramid = 3.75 ft³

V of the rectangular prism = 15 ft³

3.75 + 15 = 18.75

Hope this helped!! :)

You might be interested in

Show all work please

gayaneshka [121]

Angles D and F are supplementary, so
.. (19x -26) +(7x -2) = 180
.. 26x = 208
.. x = 208/26 = 8

∠EFG = (7x -2)° = (7*8 -2)° = 54°

Selection C is appropriate.

7 0

3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

10 months ago

Which point is a solution to the inequality shown in this graph? (3,-1) (-3,-3)

Ne4ueva [31]

Answer: try c (1,5)

Step-by-step explanation: hey eri-chan

5 0

3 years ago

44 lb 6 oz = ____ ounces

hodyreva [135]

Answer:

710 oz

Step-by-step explanation:

5 0

2 years ago

the area of a rectangle is x²-3x-10. what is the length of the rectangle if the with is x +2.?plsss asap

Inga [223]

Answer:

x - 5

Step-by-step explanation:

x^2 - 3x - 10

= (x + 2)(x - 5)

Sine the width is (x + 2), the length is (x - 5).

Hope this helped!

7 0

3 years ago