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forsale [732]
3 years ago
15

50 points! ASAP!

Mathematics
2 answers:
hichkok12 [17]3 years ago
8 0

First, find the volume of the pyramid on top:

(2.5 * 3 * 1.5) / 3 = 3.25

Then, find the volume of the rectangular prism:

2.5 * 3 * 2 = 15

Add the two volumes together:

3.25 + 15 = 18.25

To explain: you found the volume of each separate part and added it together.

Mademuasel [1]3 years ago
7 0

Answer:

<em>V = 18.75</em>

<em>Method: First find the area of the pyramid on top, then find the area of the rectangular prism below.</em>

V of the pyramid = 3.75 ft³

V of the rectangular prism = 15 ft³

3.75 + 15 = 18.75

Hope this helped!!  :)

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y=mx+b

y=x+3

Step-by-step explanation:

m: 1 (rise over run by 1)

b: 3

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What is y-1 =2(x +3) in standard form?
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Answer:

y-1=2(x+3)

y-1=2x+6

y=2x+6+1

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I think see what circuit is connected to the light

Step-by-step explanation:

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3 years ago
What is the area of a triangle with a base of five units and a height of 15 units
Leviafan [203]

Answer:

37.5

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4 0
3 years ago
Which of the following is a like radical to RootIndex 3 StartRoot 7x EndRoot?
lana [24]

Answer:

A. 4 (RootIndex 3 StartRoot 7 x EndRoot)  or 4(\sqrt[3]{7x})

Step-by-step explanation:

Given:

A radical whose value is, r_1=\sqrt[3]{7x}

Now, we need to find the like radical for r_1.

Let the like radical be r_2.

As per the definition of like radicals, like radicals are those that can be expressed as multiples of each other.

So, if two radicals r_1\ and\ r_2 are like radicals, then

r_1 = n \times r_2&#10;

Where, 'n' is a real number.

Here, r_1=\sqrt[3]{7x}

Now, let us check all the options .

Option A:

4 (RootIndex 3 StartRoot 7 x EndRoot) or r_2=4\sqrt[3]{7x}

Now, we observe that r_2 is a multiple of r_1 because

r_2=4\times \sqrt[3]{7x}\\\\ r_2=4\times r_1..............(r_1=\sqrt[3]{7x})

Therefore, option A is correct.

Option B:

StartRoot 7 x EndRoot or r_2=\sqrt{7x}

As the above radical is square root and not a cubic root, this option is incorrect.

Option C:

x (RootIndex 3 StartRoot 7 EndRoot) or r_2=x\sqrt[3]{7}

As the term inside the cubic root is not same as that of r_1, this option is also incorrect.

Option D:

7 StartRoot x EndRoot or r_2=7\sqrt{x}

As the above radical is square root and not a cubic root, this option is incorrect.

Therefore, the like radical is option (A) only.

4 0
3 years ago
Read 2 more answers
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