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2 years ago

How do I do this ( answer please )

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

8 0

Answer:

I think see what circuit is connected to the light

Step-by-step explanation:

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What is the answer to 717/3

rosijanka [135]

Answer:

717/3 = $237\frac{2}{3}$

4 0

2 years ago

Find the smallest zero of f(x+5)

podryga [215]

ANSWER

1. k=13

2. x=-10

EXPLANATION

The given function is

$f(x) = {x}^{2} + 3x - 10$

To find f(x+5), plug in (x+5) wherever you see x.

This implies that:

$f(x) = {(x + 5)}^{2} + 3(x + 5) - 10$

Expand:

$f(x) = {x}^{2} + 10x + 25+ 3x + 15- 10$

Simplify to obtain

$f(x) = {x}^{2} + 13x + 30$

We now compare with,

$f(x) = {x}^{2} + kx + 30$

This implies that:

$k = 13$

To find the smallest zero of f(x+5), we equate the function to zero and solve for x.

${x}^{2} + 13x + 30 = 0$

${x}^{2} + 10x + 3x + 30 = 0$

$x(x + 10) + 3(x + 10) = 0$

$(x + 3)(x + 10) = 0$

$x = - 10 \: or \: x = - 3$

The smallest zero is -10.

7 0

2 years ago

Read 2 more answers

Find 10 partial sums of the series. (round your answers to five decimal places.) ∞ 15 (−4)n n = 1

nikklg [1K]

Given

$\Sigma_{n=1}^\infty15(-4)^n$

The first 10 partial sums are as follows:

$S_1=\Sigma_{n=1}^{1}15(-4)^n=15(-4)=\bold{-60} \\ \\ S_2=\Sigma_{n=1}^{2}15(-4)^n=\Sigma_{n=1}^{1}15(-4)^n+15(-4)^2 \\ =-60+15(16)=-60+240=\bold{180} \\ \\ S_3=\Sigma_{n=1}^{3}15(-4)^n=\Sigma_{n=1}^{2}15(-4)^n+15(-4)^3 \\ =180+15(-64)=180-960=\bold{-780} \\ \\ S_4=\Sigma_{n=1}^{4}15(-4)^n=\Sigma_{n=1}^{3}15(-4)^n+15(-4)^4 \\ =-780+15(256)=-780+3,840=\bold{3,060} \\ \\ S_5=\Sigma_{n=1}^{5}15(-4)^n=\Sigma_{n=1}^{4}15(-4)^n+15(-4)^5 \\ =3,060+15(-1,024)=3,060-15,360=\bold{-12,300}$

$S_6=\Sigma_{n=1}^{6}15(-4)^n=\Sigma_{n=1}^{5}15(-4)^n+15(-4)^6 \\ =-12,300+15(4,096)=-12,300+61,440=\bold{49,140}$

The rest of the partial sums can be obtained in similar way.

7 0

2 years ago

Teresa is in need for help ;-; pls help her! (lolllllllllllllllllllllllllllllllllllllllllllllllllll)

nata0808 [166]

90

the answer is 90 but the answer i give has to be over 20 characters so i'm typing random things. have a good day:)

4 0

2 years ago

Read 2 more answers

This is the previous problem: A rabbit started at point 0 and made 3 jumps a jump of 4 units then a jump of 2 units and then a j

morpeh [17]

Answer:

Q1: The rabbit could be at eight different numbers of the number line: -7, - 5, - 3, - 1, 1, 3, 5, and 7.

Q2: 13

Step-by-step explanation:

Q1: Let's simulate each of the jumps of the rabbit in all the possible directions, as follows:

Option 1: - 4 - 2 - 1 = -7

Option 2: - 4 - 2 + 1 = -5

Option 3: - 4 + 2 - 1 = - 3

Option 4: - 4 + 2 + 1 = - 1

Option 5: 4 - 2 - 1 = 1

Option 6: 4 - 2 + 1 = 3

Option 7: 4 + 2 - 1 = 5

Option 8: 4 + 2 + 1 = 7

Q2: If the rabbit started at 10 you would add 3 to 10 and get 13.

7 0

2 years ago