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photoshop1234 [79]
3 years ago
14

How do I do this ( answer please )

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

I think see what circuit is connected to the light

Step-by-step explanation:

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What is 2/9 = 4/x+8 i dont get this fraction solving
Dmitriy789 [7]

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\frac{2}{9}  =  \frac{4}{x + 8}  \\

\frac{4}{x + 8}  =  \frac{2}{9}  \\

Inverse both sides

\frac{x + 8}{4}  =  \frac{9}{2}  \\

Multiply sides by 4

4 \times  \frac{x + 8}{4}  = 4 \times  \frac{9}{2}  \\

x + 8 = 2 \times 9

x + 8 = 18

Subtract sides 8

x + 8 - 8 = 18 - 8

x = 10

Done...

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3 0
2 years ago
(3t^2+1)-t^2. How do you do this equation and what’s the answer. Algebra 1.
Oksana_A [137]

2t^2+1

Subtract t^2 from 3t^2 you get 2t^2

which is 2t^2+1 answer

3 0
3 years ago
Write the equation of the line that has a slope of -2 and goes through the point (-3,4).
liubo4ka [24]

<u>SOLUTION:</u>

General Equation: y = mx + b

.

Substitute slope = -2 into the equation:

y = -2x + b

.

Find the y-intercept:

4 = -2(-3) + b

4 = 6 + b

b = -2

.

Substitute b = -2 into the equation:

y = -2x - 2

.

Answer: y = -2x - 2

4 0
3 years ago
Read 2 more answers
A system of equations and its solution are given below.
ddd [48]

Answer:

a would be correct

Step-by-step explanation:

6 0
3 years ago
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Hi, umm pls help<br><br> 1/6(x-5)=1/2(x+6), solve for x <br><br> And can you please explain
Mumz [18]

Answer:

By solving the equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) we found that   x=\frac{23}{2} \text { or }=11 \frac{1}{2}

<u>Explanation:  </u>

Given equation,

\frac{1}{6}(x-5)=\frac{1}{2}(x+6) to find x  

Step: 1 Cross multiply the denominators 2(x-5)=6(x+6)  

Step: 2 Open brackets and simplify the term 2x-10=6x+36  

Step: 3 Bring x terms on one side and simplify the equation the equation obtained is following,  

2x-6x=36+10

 -4x=46  

-x=\frac{46}{4}=\frac{23}{2}=11 \frac{1}{2}

Therefore, we solved x value from the given equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) as x=\frac{23}{2} \text { or }=11 \frac{1}{2}.

4 0
3 years ago
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