Answer:
The Proof for question no 20 and 21 are below.
Step-by-step explanation:
20.
Given:
∠PTR≅∠RSP
PT ≅ RS
To Prove:
ΔPQT ≅ ΔRQS
Proof:
In ΔPQT and ΔRQS
Statements Reasons
1. ∠PTR ≅ ∠RSP 1 .Given
2. ∠PQT ≅ ∠ROS 2. Vertical Opposite Angle Theorem.
3. PT ≅ RS 3. Given
4. ΔPQT ≅ ΔRQS 4. By A-A-S Congruence Postulate ....Proved
21.
Given:
PO ≅ SO
O is the Mid Point of NT
To Prove:
∠N ≅ ∠T
Proof:
In ΔPON and ΔSOT
Statements Reasons
1. PO ≅ S O 1 .Given
2. ∠PON ≅ ∠SOT 2. Vertical Opposite Angle Theorem.
3. NO ≅ TO 3. O is the Mid Point of NT
4. ΔPON ≅ ΔSOT 4. By S-A-S Congruence Postulate
5. ∠N ≅ ∠T 5. Corresponding Parts of Congruent Triangles are Congruent .( CPCTC )...Proved
Answer:
5cm wide, 10cm long.
Step-by-step explanation:
I came to this answer by looking for common factors between 50 and 5, and I found 10.
5cm + 5cm = 10cm, so it works.
To confirm this, I multiplied 5 and 10 and got 50cm (squared) which works.
Answer:
x=3
Step-by-step explanation:
8:6=4:x
8x=24
x=3
Answer:
The domain of g(x) is -3 to infinity
Step-by-step explanation:
Given
Required
Determine the domain of g(x)
We start by expressing the content of the square root in the following form:
Subtract 3 from both sides
This can be expressed using interval notation as follows:
<em>Hence, the domain of g(x) is -3 to infinity</em>
