5.45 times what is 65 real urgent

notsponge [240]

2 1/4 is already simplified but to make it into a mixed number the answer is 9/4

5 0

2 years ago

A local factory uses a manufacturing process in which 70% of the final products meet quality standards and 30% are found to be d

frosja888 [35]

<span>Answer:
a manufacturing process has a 70% yield, meaning that 70% of the porducts are acceptable and 30% are defective. If three of the products are randomly selected, find the probability that all of them are acceptable. ---
Ans: 0.7^3 = 0.3430.</span>

8 0

3 years ago

Consider the question of whether the home team wins more than half of its games in the National Basketball Association. Suppose

spayn [35]

Answer:

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

The home team therefore wins 50% of its games

This means that $p = 0.5$

Determine the probability that the home team would win 65% or more of its games in a simple random sample of 80 games

Sample of 80 means that $n = 80$ and, by the Central Limit Theorem:

$\mu = p = 0.65$

$s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5*0.5}{80}} = 0.0559$

This probability is 1 subtracted by the pvalue of Z when X = 0.65. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.65 - 0.5}{0.0559}$

$Z = 2.68$

$Z = 2.68$ has a pvalue of 0.9963

1 - 0.9963 = 0.0037

0.0037 = 0.37% probability that the home team would win 65% or more of its games in a simple random sample of 80 games

7 0

2 years ago

The length of a rectangle is 8 inches more than three times the width. the perimeter is 88 inches. find the length and width.

Sav [38]

We can say L as length and W as the width

L= 3w + 8

The formula for perimeter is 2L + 2W = P. We can substitute L in as "3w+8" to make the equation...

2(3w+8)+2w=88 Now, we can simplify by distributing the 2 to each term
6w+16+2w=88
8w+16=88 Then subtract 16 from each side..
8w=72
w=9

So the width is 9, so we can substitue that into the previous equation, L = 3w+8.

L=3(9)+8
L=27+8
L=35, W=9

5 0

2 years ago

You and your friend are comparing two loan options for a $165,000 house. Loan 1 is a 15-year loan with an annual interest rate o

Harlamova29_29 [7]

Answer:

No, he is wrong.

Step-by-step explanation:

Since, the total payment of a loan after t years,

$A=P(1+r)^t$

Where,

P = present value of the loan,

r = rate per period ,

n = number of periods,

Given,

P = $165,000,

In loan 1 :

r = 3% = 0.03, t = 15 years,

So, the total payment of the loan is,

$A_1 = 165000(1+0.03)^{15}=165000(1.03)^{15}\approx \$ 257,064.62$

In loan 2 :

r = 4% = 0.04, t = 30 years,

So, the total payment of the loan is,

$A_2 = 165000(1+0.04)^{30}=165000(1.04)^{30}\approx \$ 535,160.59$

Since, $A_1 < A_2$

Hence, total amount repaid over the loan will be less for Loan 1.

That is, the friend is wrong.

7 0

2 years ago