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bogdanovich [222]
3 years ago
5

*Please help!* (There are more than 1 answers)

Mathematics
2 answers:
Lelu [443]3 years ago
7 0
Well, the unit rate in the table is approximately 1.143 (8/7)

So, the only lines which have unit rate in between 1.143 and 2 are Line 3 (1.5) and Line 4 (1.2).
Leviafan [203]3 years ago
7 0

Answer:

Line 3 and Line 4

Step-by-step explanation:

Table:

x    y

7    8

14   16

21    21

Unit rate of given table = Slope = \frac{y_2-y_1}{x_2-x_1}

(x_1,y_1)=(7,8)

(x_2,y_2)=(14,16)

So, Slope =  \frac{16-8}{14-7}=\frac{8}{7}=1.142

So, unit rate of the given table is 1.142

Unit rate of line 1 = \frac{y_2-y_1}{x_2-x_1}

(x_1,y_1)=(0,0)

(x_2,y_2)=(2,6)

So, Slope =  \frac{6-0}{2-0}=\frac{6}{2}=3

Unit rate of line 2 = \frac{y_2-y_1}{x_2-x_1}

(x_1,y_1)=(0,0)

(x_2,y_2)=(3,6)

So, Slope =  \frac{6-0}{3-0}=\frac{6}{3}=2

Unit rate of line 3 = \frac{y_2-y_1}{x_2-x_1}

(x_1,y_1)=(0,0)

(x_2,y_2)=(4,6)

So, Slope =  \frac{6-0}{4-0}=\frac{6}{4}=1.5

Unit rate of line 4 = \frac{y_2-y_1}{x_2-x_1}

(x_1,y_1)=(0,0)

(x_2,y_2)=(5,6)

So, Slope =  \frac{6-0}{5-0}=\frac{6}{5}=1.2

Unit rate of line 5 = \frac{y_2-y_1}{x_2-x_1}

(x_1,y_1)=(0,0)

(x_2,y_2)=(6,6)

So, Slope =  \frac{6-0}{6-0}=\frac{6}{6}=1

Now we are supposed to find he lines on the graph with unit rates that are less than 2 and greater than the unit rate of the relationship in the table.i.e. 1.14<m<2

So, the unit rate of Line 3 and Line 4 are less than 2 and greater than the unit rate of the relationship in the table

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GarryVolchara [31]
In order to divide $306 into the ratio of 9 to 5 to 3, first you have to make each section of the ratio represented by a variable, and put it into an equation.

9x + 5x + 3x = 306

Our next step is to simplify the left side of the equation by combining all of the like terms, the ones that contain variables.

17x = 306

Finally, to solve this equation, you have to divide both sides by 17 to isolate the variable x on the left side of the equation.

x = 18

However, this is not our answer as it isn't in a ratio format and doesn't really make sense. To find our ratio, we have to multiply each of our initial numbers (9, 5, and 3) by our variable, x.

9 * 18 = 162
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Your final ratio is 162:90:54.

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4 0
3 years ago
Only the function represented by graph has an inverse function.
Arlecino [84]

Answer:

Only the function represented by graph 2 has an inverse function

Step-by-step explanation:

* Lets explain the inverse of the function

- The Function is a relation between x-coordinates and the y-

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- Ex: R = {(2 , 3) , (1 , 5) , (-2 , -3)} is a function because every x-

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 (2 , 5)} not a function because the x-coordinate 2 has two y-

 coordinates 3 and 5

- We use the vertical line to test the graph is function or not, if

 the vertical line intersects the graph in one point then the

 graph is function if intersects it in more than one point then the

 graph is not function

- We have two types of function one-to-one function and

 many-to-one function

# one-to-one function means every x-coordinate has only 1 y-coordinate

# many-to-one function means some x-coordinates have only 1

  y-coordinate

- We find the inverse function by switching x and y, then one-to-

 one function has inverse but many-to-one has not inverse

 because when we switched x and y it will be one-to-many

 means one x-coordinate has many y-coordinates and this is not

 a function

- We use the horizontal line to test the graph of the function has

 inverse or not, if the horizontal line intersects the graph in one

 point then the function of the graph has inverse if it intersects

 the graph in more than one point ,then the function of the  

 graph has no inverse

* Now lets test all the graphs by using the horizontal line

# graph 1

∵ The horizontal line cuts the graph in more than 1 point

∴ The function of graph 1 has no inverse

# graph 2

∵ The horizontal line cuts the graph in just 1 point

∴ The function of graph 2 has inverse

# graph 3

∵ The horizontal line cuts the graph in more than 1 point

∴ The function of graph 3 has no inverse

# graph 4

∵ The horizontal line cuts the graph in more than 1 point

∴ The function of graph 4 has no inverse

* Only the function represented by graph 2 has an inverse function

4 0
3 years ago
How can you tell if a number is rational and irrational??
kompoz [17]
All numbers<span> that are not </span>rational<span> are considered </span>irrational<span>. An </span>irrational number<span> can be written as a decimal, but not as a fraction. An </span>irrational number<span> has endless non-repeating digits to the right of the decimal point.</span>
4 0
3 years ago
Read 2 more answers
Please look at this multiple choice, thanks!
Nastasia [14]

Step-by-step explanation:

\frac{y - y1}{x - x1}  =  \frac{y2 - y1}{x2 - x1}

\frac{y - 0}{x - ( - 1)}  =  \frac{3 - 0}{1 - ( - 1)}

\frac{y}{x + 1}  =  \frac{3}{1 + 1}

\frac{y}{x + 1}  =  \frac{3}{2}

y =  \frac{3}{2} (x + 1)

y =  \frac{3}{2} x +  \frac{3}{2}

option B

7 0
3 years ago
Please please help me no links
Finger [1]

Given:

In triangle ABC, AB = AC, AD is angle bisector and measure of angle C is 49 degrees.

To find:

The value of x and y.

Solution:

In triangle ABC,

AB=AC                    (Given)

So, triangle ABC is an isosceles triangle and by the definition of base angles the base angles of isosceles triangle are congruent.

In isosceles triangle ABC,

\angle B\cong \angle C

m\angle B\cong m\angle C

m\angle B\cong 49^\circ

The angle bisector of an isosceles triangle is the median and altitude of the triangle. So, the angle bisector is perpendicular to the base.

m\angle ADB=90^\circ

x^\circ=90^\circ

In triangle ABD,

m\angle DAB+m\angle ABD+m\angle ADB=180^\circ         [Angle sum property]

y^\circ+49^\circ+x^\circ=180^\circ

y^\circ+49^\circ+90^\circ=180^\circ

y^\circ=180^\circ-49^\circ-90^\circ

y^\circ=41^\circ

Therefore, the correct option is B.

3 0
3 years ago
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