Question

*Please help!* (There are more than 1 answers)

Answer 1

Well, the unit rate in the table is approximately 1.143 (8/7)

So, the only lines which have unit rate in between 1.143 and 2 are Line 3 (1.5) and Line 4 (1.2).

Answer 2

Answer:

Line 3 and Line 4

Step-by-step explanation:

Table:

x    y

7    8

14   16

21    21

Unit rate of given table = Slope = $\frac{y_2-y_1}{x_2-x_1}$

$(x_1,y_1)=(7,8)$

$(x_2,y_2)=(14,16)$

So, Slope =  $\frac{16-8}{14-7}=\frac{8}{7}=1.142$

So, unit rate of the given table is 1.142

Unit rate of line 1 = $\frac{y_2-y_1}{x_2-x_1}$

$(x_1,y_1)=(0,0)$

$(x_2,y_2)=(2,6)$

So, Slope =  $\frac{6-0}{2-0}=\frac{6}{2}=3$

Unit rate of line 2 = $\frac{y_2-y_1}{x_2-x_1}$

$(x_1,y_1)=(0,0)$

$(x_2,y_2)=(3,6)$

So, Slope =  $\frac{6-0}{3-0}=\frac{6}{3}=2$

Unit rate of line 3 = $\frac{y_2-y_1}{x_2-x_1}$

$(x_1,y_1)=(0,0)$

$(x_2,y_2)=(4,6)$

So, Slope =  $\frac{6-0}{4-0}=\frac{6}{4}=1.5$

Unit rate of line 4 = $\frac{y_2-y_1}{x_2-x_1}$

$(x_1,y_1)=(0,0)$

$(x_2,y_2)=(5,6)$

So, Slope =  $\frac{6-0}{5-0}=\frac{6}{5}=1.2$

Unit rate of line 5 = $\frac{y_2-y_1}{x_2-x_1}$

$(x_1,y_1)=(0,0)$

$(x_2,y_2)=(6,6)$

So, Slope =  $\frac{6-0}{6-0}=\frac{6}{6}=1$

Now we are supposed to find he lines on the graph with unit rates that are less than 2 and greater than the unit rate of the relationship in the table.i.e. 1.14<m<2

So, the unit rate of Line 3 and Line 4 are less than 2 and greater than the unit rate of the relationship in the table