The relationship between energy of a single photon and its wavelength can be determined using the formula E=hc/lambda where E is energy, h is Planck's constant, c is the speed of light, and lambda is photons.
Before being able to solve for energy, need to convert nanometers to meters.
407 nm (1 m/1 x 10^9 nm) = 4.07 x 10^-7 m
Then plug in the values we know into the equation.
E h(Planck's constant) c(speed of light)
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / 4.07 x 10^-7 m (lambda)
E=(0.000000000000000000000000000000000663js)(300,000,000m/s)=1.989×10^-25j/ms
E=1.989x10^-25j/ms /{divided by} 4.07x10^-7m = 4.8869779x10^-33 J (the meters cancel out)
E = 4.89 x 10^-33 J
This gives us the energy in Joules of a single photon. Now, we can find the number of photons in 0.897 J
0.897J / 4.89 x 10^-33 J = ((0.897 J) / 4.89) x ((10^(-33)) J) = 1.8343558 x 10^-34
1.83435583 × 10-34m4 kg2 / s4 photons
Si has the largest, then S, then O
If we have in mind the following procedure:
BACo3(s) + H +1 -> Ba +2 + HCO3 -1
CO3 - 2 + H+1 -> HCO3 -1
As nitric acid is added then {CO3 -2 } decreases meaning that more BaCo3 can dissolve. The graph you need to use is the one that the curve goes down and closer to solubility and goes up on conc.
Group (1) is alkali metal and its elements have 1 valence electron. Oxygen (O) valency is 2, and together they can form compounds with the general formula X2O.
Therefore, (1) Group 1 is the correct answer.
Hope this helps~
