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Soloha48 [4]
3 years ago
14

A sample of an unknown metal has a mass of 6.557 g. The metal was carefully added to a graduated cylinder containing 10.50 mL of

water. The water level in the graduated cylinder rose to 11.16 mL. What is the density of the unknown metal?​
Chemistry
1 answer:
Levart [38]3 years ago
8 0

Answer:

Explanation:

Be careful. The tricky part of the problem is that there are 4 places of sig digs.

m = 6.557 grams

V = 11.16 - 10.50 = 0.66

density = mass/ volume

density = 6.557/0.66 = 9.935 g/mL

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Helium

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3 0
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The blue color of the sky results from the scattering of sunlight by air molecules. The blue light has a frequency of about 7.5
vazorg [7]

A) c = 3 x 10^8 m/s 
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Read more on Brainly.com - brainly.com/question/5760368#readmore
3 0
3 years ago
How many milligrams of MgI2 must be added to 257.7 mL of 0.087 M KI to produce a solution with [I−] = 0.1000 M?
lbvjy [14]

Answer:

The answer is 465.6 mg of MgI₂ to be added.

Explanation:

We find the mole of ion I⁻ in the final solution

C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol

But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.

So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.

Hence, the weight of MgI₂ must be added is

Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg

4 0
3 years ago
PLEASE EXPLAIN CORRECTLY! THX=)
tankabanditka [31]
A way to explain it is that back then all the continents were together but soon after drifted apart the were in the same place sort of put they drifted apart so that's sorta what happened. Hope that helps a little
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