Answer:
<h2>22.366 kPa</h2>
Explanation:
The final pressure can be found by using the formula for Boyle's law which is
Since we are finding the final pressure
From the question
58.6 kPa = 58600 Pa
We have
We have the final answer as
<h3>22.366 kPa</h3>
Hope this helps you
First, we write the reaction for CH3OH combustion
CH3OH+3/2O2--->CO2+2H2O
for 1 mole of methanol, we get 1 mole of CO2, therefore for 5,25 moles of methanol we will get 5,25 moles of CO2
Answer:
The answer to your question is 35.4527 g
Explanation:
Data
Cl-35 abundance = 75.77 % mass Cl-35 = 34.9688
Cl-37 abundance = 24.23 % mass Cl-37 = 36.9659
Process
1.- Convert the percents to decimals
75.77% = 75.77/100 = 0.7577
24.23% = 24.23/100 = 0.2423
2.- Find the atomic weight
Average atomic weight = Abundance 1 x Mass Cl-35 +
Abundance 2 x Mass Cl-37
Substitution
Average atomic weight = (0.7577)(34.9688) + (0.2423 x 36.9659)
Simplification
Average atomic weight = 26.4959 + 8.9568
Result
Average atomic weight = 35.4527 g
Answer:
D.) 2 H₂ + O₂ -----> 2 H₂O
Explanation:
An equation is balanced when there is an equal amount of each element on both sides of the reaction. If these amounts are unequal, coefficients can be added to modify the amount of particular molecules.
A.) Not balanced
2 H₂ + 2 O₂ -----> H₂O
<u>Reactants</u>: 4 hydrogen, 4 oxygen
<u>Products</u>: 2 hydrogen, 1 oxygen
B.) Not balanced
2 H₂ + 2 O₂ -----> 2 H₂O
<u>Reactants</u>: 4 hydrogen, 4 oxygen
<u>Products</u>: 4 hydrogen, 2 oxygen
C.) Not balanced
H₂ + O₂ -----> H₂O
<u>Reactants</u>: 2 hydrogen, 2 oxygen
<u>Products</u>: 2 hydrogen, 1 oxygen
D.) Balanced
2 H₂ + O₂ -----> 2 H₂O
<u>Reactants</u>: 4 hydrogen, 2 oxygen
<u>Products</u>: 4 hydrogen, 2 oxygen
Mmncotiuy unscrambled would be Community
