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anastassius [24]
3 years ago
11

If you drop a bowling ball, a tennis ball, and a feather from the top of a tall building at the same time, which one will hit th

e ground first in the absence of air resistance?
Physics
2 answers:
olasank [31]3 years ago
8 0

They hit at the same time. Everything falls at the same rate.

Jlenok [28]3 years ago
4 0

Answer:

All arrive at the same time on the ground.

Explanation:

For this exercise let's use Newton's second law

                F = m a

The force is the attraction of gravity of the Earth on the body

              F = W = mg

Let's replace

             m g = m a

             a = g

We can see that the acceleration of the body is independent of its masses, so that the three bodies, bowling, tennis and pen have the same acceleration and as the three legs of rest. All arrive at the same time on the ground.

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AveGali [126]

Correct answer choice is:

C. Polarized in a vertical plane.

Explanation:

Polarized sunglasses give excellent glare shield, particularly on the water. Polarized lenses include a specific filter that prevents this type of strong reflected light, diminishing glare.

This is because when you angle one polarized lens to different perpendicularly, they prevent glare both horizontally and vertically. The polarized lenses are enduringly tinted sunglasses that exceedingly decrease glare.

7 0
3 years ago
Which planet has the GREATEST attraction to the sun?
AveGali [126]
I think its Mercury because it's the closest to the sun.
3 0
3 years ago
The unit of measurement "mL" describes what property of a substance?
pychu [463]
<span>D. density is your answer</span>
8 0
3 years ago
Read 2 more answers
Saturated steam at 125 kpa is compressed adiabatically in a centrifugal compressor to 700 kpa at the rate of 2.5 kg⋅s−1. the com
Tpy6a [65]
M° = 2.5 kg/sec
For saturated steam tables
at p₁ = 125Kpa
hg = h₁ = 2685.2 KJ/kg
SQ = s₁ = 7.2847 KJ/kg-k
for isotopic compression
S₁ = S₂ = 7.2847 KJ/kg-k
at 700Kpa steam with S = 7.2847
h₂ 3051.3 KJ/kg
Compressor efficiency
h =  0.78
0.78 = h₂ - h₁/h₂-h₁
0.78 = h₂-h₁ → 0.78 = 3051.3 - 2685.2/h₂ - 2685.2
h₂ = 3154.6KJ/kg
at 700Kpa with 3154.6 KJ/kg
enthalpy gives
entropy S₂ = 7.4586 KJ/kg-k
Work = m(h₂ - h₁) = 2.5(3154.6 - 2685.2
W = 1173.5KW
5 0
3 years ago
6. A 73-kg woman stands on a scale in an elevator. The
olga nikolaevna [1]

Answer:

b

Explanation:

n = m(g +a)

n= normal force (N)

m=mass (kg)

g=acceleration of gravity

a= acceleration of elevator

rearrange:

a= n/m - g

a= (810 N/73 kg) - 9.8 m/s ^2

a= 1.3 m/s ^2 up

and the acceleration is upwards bc her weight is less than the scale reading

3 0
3 years ago
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