1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aivan3 [116]
3 years ago
7

A block of mass 10 kg slides down an inclined plane that has an angle of 30. If the inclined plane has no friction and the block

starts at a height of 2 m, how much kinetic energy does the block have when it reaches the bottom? Acceleration due to gravity is g = 9.8 m/s2.
Physics
2 answers:
Alchen [17]3 years ago
6 0

Answer:

E = 196 joules

Explanation:

It is given that,

Mass of the block, m = 10 kg

At the top, the block will have only potential energy which is given by :

P=mgh

At the bottom of the inclined plane, it will have only kinetic energy which is given by :

E=\dfrac{1}{2}mv^2

Applying the conservation of energy as :

E=\dfrac{1}{2}mv^2=mgh

E=10\ kg\times 9.8\ m/s^2\times 2\ m

E = 196 joules

So, the block will have 196 joules of kinetic energy when it reaches the bottom. Hence, this is the required solution.

Helga [31]3 years ago
4 0
No friction present means: Ek = Ep

So Ek = mgh = 10 * 9.8 * 2 = 196 J
You might be interested in
This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The mag
Dmitry [639]

Answer:

Part a)

F = 135.7 N

Part b)

F = 62.5 N

Explanation:

Part a)

If block is sliding up then net force must be zero and friction will be in opposite to the direction of motion of the block

Fcos\theta = mg + F_f

Fsin\theta = F_n

so we have

Fcos\theta = mg + \mu(Fsin\theta)

F(cos\theta - \mu sin\theta) = mg

F = \frac{mg}{cos\theta - \mu sin\theta}

F = \frac{55}{cos50 - 0.310(sin50)}

F = 135.7 N

Part b)

If block is sliding down then net force must be zero and friction will be in opposite to the direction of motion of the block

Fcos\theta = mg - F_f

Fsin\theta = F_n

so we have

Fcos\theta = mg - \mu(Fsin\theta)

F(cos\theta + \mu sin\theta) = mg

F = \frac{mg}{cos\theta + \mu sin\theta}

F = \frac{55}{cos50 + 0.310(sin50)}

F = 62.5 N

6 0
3 years ago
Modify how could you charge the electric circuit shown below to allow lightbulb a to stay lit even if lightbulb b is removed fro
shepuryov [24]
When a circuit is complete, or closed, electrons can flow from one end of a battery all the way around, through the wires, to the other end of the battery. Along its way, it will carry electrons to electrical objects that are connected to it – like the light bulb – and make them work!
5 0
2 years ago
A little girl is going on the merry-go-round for the first time, and wants her 50kg mother to stand near to her on the ride 2.1m
aliya0001 [1]
Angular momemtum : mass * tangential speed * distance to the center = 50*2.1*3.6=37800 J.s
3 0
3 years ago
The momentum of a falling rock is found to be 200 kg m/s. What is the mass of the rock if it falls with a velocity of 5.0 m/s
Snezhnost [94]

Answer:

\boxed {\boxed {\sf 40 \ kilograms}}

Explanation:

Momentum is the product of velocity and mass. The formula is:

p=m*v

We know the rock is falling. Its momentum is 200 kilograms meters per second and its velocity is 5 meters per second. Substitute the values into the formula.

200 \ kg \ m/s = m * 5.0 \ m/s

We are solving for m, the mass. We must isolate the variable. It is being multiplied by 5 meters per second. The inverse of multiplication is division, so we divided both sides by 5.0 m/s.

\frac{200 \ kg \ m/s}{5.0 \ m/s}=\frac{ m* 5.0 \ m/s }{5.0 \ m/s}

\frac{200 \ kg \ m/s}{5.0 \ m/s}=m

The units of meters per second (m/s) cancel.

\frac{200 \ kg}{5.0 } =m

40 \ kg = m

The falling rock has a mass of <u>40 kilograms.</u>

4 0
2 years ago
Two or more velocities add by ____?<br><br> Plz help
VladimirAG [237]
By vector addition.
In fact, velocity is a vector, with a magnitude intensity, a direction and a verse, so we can't simply do an algebraic sum of the two (or more velocities). 
First we need to decompose each velocity on both x- and y-axis (if we are on a 2D-plane), then we should do the algebraic sum of all the components on the x- axis and of all the components on the y-axis, to find the resultants on x- and y-axis. And finally, the magnitude of the resultant will be given by
R= \sqrt{(R_x)^2+(R_y)^2}
where Rx and Rx are the resultants on x- and y-axis. The direction of the resultant will be given by
\tan \alpha =  \frac{R_y}{R_x}
where \alpha is its direction with respect to the x-axis.
3 0
3 years ago
Read 2 more answers
Other questions:
  • A person speed walking down a street covers 20m in 5s. What is the<br> speed of the individual? *
    7·1 answer
  • A solar collector receives solar radiation at a rate of 0.315 kW per m²and delivers the heat to a storage unit whose temperature
    14·1 answer
  • An electron enters a region of space containing a uniform 0.0000193-T magnetic field. Its speed is 121 m/s and it enters perpend
    12·1 answer
  • HELP A car traveling at 4m/s accelerates at a rate of .80m/s2 for 1.8s. What is its final velocity?
    8·2 answers
  • What are the units of the following properties? Enter your answer as a sequence of five letters separated by commas, e.g., A,F,G
    7·1 answer
  • What is the most fundamental property of a star in determining its evolution? luminosity temperature composition mass size?
    5·1 answer
  • What sound signal alerts others that a boat is backing up?
    11·1 answer
  • Leslie is investigating which brand of cell phone has the longest lasting battery.
    8·1 answer
  • A metal wire has a resistance of 13.00 at a temperature of 25.0 degree celsius
    15·1 answer
  • 1. Describe the three Newton's Law of Motion.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!