The fast runner will cover 8 km by time = t = d/v =8/14.8 = 0.54 hour
at that time ( 0.54 hr ) the slower runner would cover d = v*t = 11*.0.54 = 5.94 km
So the slower would be at a distance = 8km - 5.94km =2.06 km from the finish line.
Complete Question
A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.38 T perpendicular to the electric field also exists in this region. A beam of positively charged particles travels into the region. Determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (Assume the beam of particles travels perpendicularly to both fields.)
Answer:
The velocity is
Explanation:
From the question we are told that
The magnitude of the electric field is 
The magnetic field is 
The force due to the electric field is mathematically represented as

and
The force due to the magnetic field is mathematically represented as

Now given that it is perpendicular , 
=> 
=> 
Now given that it is not deflected it means that

=> 
=> 
substituting values


The corresponding downward force on the top of a horizontal square is 375 lb.in
<h3>What is pressure?</h3>
The pressure is the amount of force applied per unit area. It is represented as
Pressure p = Force/Area
If the atmospheric pressure is 15 lb/in and area 5 inches on each side is
A = 5² = 25 in²
The force applied is
15 lb/in = F /25 in²
F = 375 lb.in
Hence, the corresponding downward force on the top of a horizontal square is 375 lb.in
Learn more about pressure.
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Answer:
Explanation:
Given that,
Initial Angular velocity w=500rpm
Converting from rpm to rad/s
1rev =2πrad
1minutes =60secs
500rpm=500rev/mins
w = 500×2π/60
wi=52.36rad/s
The final angular velocity wf=0rad/s
Time to stop is t=2.6sec
We want to find angular acceleration α
Using the equation of angular motion
wf = wi + αt.
0 = 52.36 + 2.6α
-52.36=2.6α
α = -52.36/2.6
α = -20.14rad/s²
The angular acceleration is negative because it is decelerating.
Then, α=20.14rad/s²