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4 years ago

Which elements will bond ionically with barium such that the formula would be written as BaX2?

Physics

2 answers:

kondor19780726 [428]4 years ago

6 0

Explanation:

Barium is a metal and has excess of electrons. Thus, in order to become stable barium will donate its extra electrons to an electron deficient atom. As a result, there will be formation of ionic bond.

Non-metals have deficiency of electrons and thus, they will readily accept electrons from barium in order to complete their octet. Mostly non-metals have a charge of -1.

Therefore, they will combine with barium to form a compound with formula $BaX_{2}$ .

For example, when barium combines with fluorine, the formula will be $BaF_{2}$ .

Hence, we can conclude that barium can combine with fluorine, iodine, chlorine, and bromine such that the formula could be written as $BaF_{2}$ .

Cerrena [4.2K]4 years ago

3 0

Chlorine, iodine, and fluorine <span> will bond ionically with barium such that the formula would be written as BaX2.</span>

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Explanation:

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v = fλ

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We can find a wavelength for the sound within this range, so as to obtain the exact frequency.

The options include 2001, 2033, 2127, 2095, or 2064 Hz.

Taking just 1 frequency in that range, f = 2033 Hz.

v = fλ

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Inserting in the destructive interference equation

(m + ½)λ = 1.1

If λ = 0.169 m

(m + ½) = (1.1/0.169) = 6.5

m + ½ = 6.5

Hence, it is evident that m = 6 for this question.

And the corresponding frequency at this level of destructive interference is 2033 Hz

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