All categories

2 years ago

What does x equal in the function: f(-11)=5x+1

Mathematics

1 answer:

mestny [16]2 years ago

4 0

Answer:i believe the answer is -54

Hope this helped!

Step-by-step explanation:

You might be interested in

How do you solve a quadratic function using x^2+bx+c?

enot [183]

Answer:

Check the attachment, then plug in values as needed

Step-by-step explanation:

4 0

2 years ago

Anything for this one?

Sergeeva-Olga [200]

Answer:

A. -2

Step-by-step explanation:

Hope this helps

6 0

2 years ago

Read 2 more answers

How to find the inverse of 3log3(x+3)+1. Its with a base of 3

Natasha_Volkova [10]

Let $f^{-1}(x)$ be the inverse of

$f(x) = 3 \log_3 (x + 3) + 1$

Then by definition of inverse function,

$f\left( f^{-1}(x) \right) = 3 \log_3 \left(f^{-1}(x) + 3\right) + 1 = x$

Solve for the inverse :

$3 \log_3 \left(f^{-1}(x) + 3\right) + 1 = x$

$3 \log_3 \left(f^{-1}(x) + 3\right) = x - 1$

$\log_3 \left(f^{-1}(x) + 3\right) = \dfrac{x - 1}3$

$3^{\log_3 \left(f^{-1}(x) + 3\right)} = 3^{\frac{x-1}3}$

$f^{-1}(x) + 3 = 3^{\frac{x-1}3}$

$f^{-1}(x) = 3^{\frac{x-1}3} - 3$

5 0

2 years ago

A restaurant owner was experimenting with the taste of her homestyle lemon drink. She started with 60 litres of water. She remov

Burka [1]

Answer:

ratio of pure lemon juice to water in the homestyle lemon drink is 5 : 19.

Step-by-step explanation:

In order to solve the final ratio of lemon juice to water, let us start by determining the initial ratio of pure lemon juice to water in the first mix. This is done as follows:

Total volume of mixture = 60 liters

initial volume of water = 60 liters

initial volume of lemon juice = 0 liters

1) She removed 15 liters of the water and replaced it with 15 liters of pure lemon juice.

Volume of water = 60 - 15 = 45 liters

Volume of lemon juice = 15 liters

$\therefore \frac{15}{60}\ = \frac{1}{4}\ of\ the\ first\ mix\ is\ lemon\ juice\\\frac{45}{60}\ = \frac{3}{4}\ of\ the\ first\ mix\ is\ pure\ water$

2) She removed 10 liters of the new mixture

Let us convert this amount removed into ratio:

$lemon\ juice\ = \frac{1}{4}\ \times 10 = \frac{10}{4} = \frac{5}{2}\ liters.\\ \therefore the\ owner\ removes\ \frac{5}{2}\ liters\ of\ pure\ lemon\ juice\\pure\ water\ = \frac{3}{4}\ \times 10 = \frac{30}{4} = \frac{15}{2}\ liters\\ \therefore\ the\ owner\ removes\ \frac{15}{2}\ liters\ of\ water\ from\ the\ first\ mix.$

New volumes of water and lemon juice after removing the 10 liters of mixture is calculated as follows:

$lemon\ juice\ = 15 - \frac{5}{2} = \frac{30-5}{2} = \frac{25}{2}\ liters\ of\ lemon\ juice\\pure\ water\ = 45 - \frac{15}{2} = \frac{90-15}{2} = \frac{75}{2}\ liters\ of\ pure\ water$