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galben [10]
3 years ago
14

The triangles are similar. solve for x

Mathematics
1 answer:
Reptile [31]3 years ago
4 0

Answer:

x= 6.25

Step-by-step explanation:

The hypotenuse of triangle JKL is taken as 96, in the similar way the hypotenuse of triangle JTU is 36. So x can be found by first finding the value of JU, using the Pythagoras theorem.

a^{2} = b^{2} + c^{2}

In this shape the formula will be:

TU^{2} = JT^{2} + JU^{2}

Substitute the given values in the shape into the formula.

TU = 34

JT = 27

TU = Lets take 'y'

34^{2} = 27^{2} + y^{2}

1156 = 729 + y^{2}

y^{2} = 1156 - 729

y^{2} = 427

y = \sqrt{427} = 20.7 ( rounded to 1 decimal place) = 21 (rounded to whole number).

So the original value of JU is '21', but we have to find the value of 'x'. So the expression '-4 + 4x' is equal to 21. This can be written as:

-4 + 4x = 21

4x = 21 + 4

4x = 25

∴ x = \frac{25}{4} = 6.25

x= 6.25

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i x i = j x j = k x k = 0

i x j = k

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The cross product is antisymmetric, or anticommutative, meaning that for any  vectors u and v, we have u x v = - (v x u).

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