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Mazyrski [523]
3 years ago
13

What is the 8th term in the sequence? an=25−3n Enter your answer in the box.

Mathematics
2 answers:
MakcuM [25]3 years ago
7 0

Answer:

The answer to this question is going to be 1

Step-by-step explanation:

Hope this will help someone out :)

rosijanka [135]3 years ago
6 0
What is the 8th term in the sequence?


an=25−3n
n=term
n=8

a(8)=25-3(8)
a(8)=25-24
a(8)=1
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Answer:

\large\boxed{x=\dfrac{3\pi}{2}\ \vee\ x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}}

Step-by-step explanation:

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\sin x=-1\to x=-\dfrac{\pi}{2}+2k\pi,\ k\in\mathbb{Z}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}\\\\x\in[0,\ 2\pi)

x=-\dfrac{\pi}{2}\notin[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+2\pi=\dfrac{3\pi}{2}\in[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+4\pi=\dfrac{7\pi}{2}\notin[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}+2\pi=\dfrac{13\pi}{6}\notin[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}+2\pi=\dfrac{17\pi}{6}\notin[0,\ 2\pi)

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6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find  how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

Trenton's pet: 4/5 cup of dry food•

With 4/5 per day , for 14 days :

⇒ 14(\frac{4}{5} )

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Maria's pet: 1.25 cups of dry food.

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Subtracting Maria's - Trenton's :

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That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

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3 years ago
Answer to this please! Thank you :))))
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Answer:

62

Step-by-step explanation:

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