suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
. . Hmmmmmmmmm, I wonder what the answer could be XD
Answer: Increase in number or size, at a constantly growing rate. It is one possible result of a reinforcing feedback loop that makes a population or system grow (escalate) by increasingly higher amounts.
Answer: x= -6
Step-by-step explanation:
It will be a vertical line parallel to the y-axis at -6 on the x-axis. It passes through every y-value, including the given -5 and -2
Answer:
Check whether the first and last terms of the trinomial are perfect squares.
Multiply the roots of the first and third terms together.
Compare to the middle terms with the result in step two
If the first and last terms are perfect squares, and the middle term’s coefficient is twice the product of the square roots of the first and last terms
Step-by-step explanation:
