Sense, the recipe would then have to be using as a whole of 4/5 of water, we would then, have to divide 4/5 by 1/3, and by us doing this, we would then get our answer as the following:
Answer:
Outliers affect the mean value of the data but have little effect on the median or mode of a given set of data.
Is there any more details, I could give a better answer.
Yes
U r very good
Can u teach me I’m new
My actual name Naheed
<span>let x = the number of liters of the 20% solution.
let y = the number of liters of the 60% solution.
you want x + y to be equal to 40 liters.
x is the number of liters total in the first solution.
y is the number of liters total in the second solution.
you want .2 * x + .6 * y to be equal to .35 * 40
.2 * x is the number of liters of acid in the first solution.
.6 * y is the number of liters of acid in the second solution.
.35 * 40 is the number of liters of acid in the final solution.
you have two equations that need to be solved simultaneously.
they are:
x + y = 40
.2x + .6y = .35*40
simplify these equations to get:
x + y = 40
.2x + .6y = 14
you can solve by substitution or by elimination or by graphing.
i will solve this one by graphing.
this means to graph both equations and find the intersection.
the graph looks like this:
the graph says the intersection is at the coordinate point of (25,15).
this means that x = 25 and y = 15.
x is the number of liters of the 20% solution.
y is the number of liters of the 60% solution.
the formula of .2x + .6y = 14 becomes .2 * 25 + .6 * 15 = 14.
simplify this equation to get 14 = 14.
this confirms the solution is good.
</span>
Answer:
Test statistics of <u>1.455 </u>
P-value = 0.0728
Step-by-step explanation:
From the given information:
The test statistics can be computed as:
Z = 1.455
We want to test if the customer satisfaction increased significantly(one-tailed test)
Null hypothesis:
Alternative hypothesis:
P-value = P(Z>1.455)
= 0.0728
b) Type II error implies the error of accepting 
when 
is true.
This implies inferring that there is no huge improvement in passenger's satisfaction when there is.
c) Type 1 and Type II errors are inversely proportional. In this situation, as one increases, the other definitely decreases.
∴ A Smaller value of Type II error will be achieved by a higher type I error.
⇒ 0.10
