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emmainna [20.7K]
3 years ago
13

The starting salaries of individuals with an MBA degree are normally distributed with a mean of $40,000 and a standard deviation

of $5,000.Refer to Exhibit 6-4. What is the probability that a randomly selected individual with an MBA degree will get a starting salary of at least $30,000
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
6 0

Answer:

P(X>30000)=P(\frac{X-\mu}{\sigma}>\frac{30000-\mu}{\sigma})=P(Z-2)

And we can find this probability using the complement rule and the normal standard distribution

P(z>-2)=1-P(z

Step-by-step explanation:

Let X the random variable that represent the starting salaries of individuals with a MBA of a population, and for this case we know the distribution for X is given by:

X \sim N(40000,5000)  

Where \mu=40000 and \sigma=5000

We are interested on this probability

P(X\geq 30000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

Using this formula we got:

P(X>30000)=P(\frac{X-\mu}{\sigma}>\frac{30000-\mu}{\sigma})=P(Z-2)

And we can find this probability using the complement rule and the normal standard distribution

P(z>-2)=1-P(z

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cupoosta [38]

Answer:

3/5 or 0.6

Step-by-step explanation:

Here, given the value of tan theta , we want to find the value of sine theta

Mathematically;

tan theta = 0pposite/adjacent

Sine theta = opposite/hypotenuse

Firstly we need the length of the hypotenuse

This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.

Let’s call the hypotenuse h

h^2 = 3^2 + 4^2

h^2 = 9 + 16

h^2 = 25

h = √(25)

h = 5

Now from the tan theta, we know that the opposite is 3

Thus, the value of the sine theta = 3/5 or simply 0.6

5 0
3 years ago
Need help how do I do this, start it, and the steps please
Harman [31]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's first write down the equation we are going to solve.

( 1 / 3 )h - 4 [ ( 2 / 3 )h - 3 ] = ( 2 / 3 )h - 6

To begin with, we will expand the brackets => [ ]

( 1 / 3 )h - ( 8 / 3 )h + 12 = ( 2 / 3 )h - 6

Next we will collect like terms by placing all the individual numbers on the right-side of the equation and the terms with ( h ) on the left-hand side of the equation so that we can begin making ( h ) the subject.

( 1 / 3 )h - ( 8 / 3 )h - ( 2 / 3 )h = - 6 - 12

Then we will simplify both the left-hand side and right-hand side of the equation to solve it for ( h ).

( - 9 / 3 )h = - 18

- 3h = - 18

h = - 18 / - 3

h = 18 / 3

h = 6

FINAL ANSWER:

Therefore, the answer is:

h = 6

Hope this helps! :)
Have a lovely day! <3
4 0
3 years ago
A pet store is having a pet fish sale. Mr. Green bought three bags of pet fish for his nephews. Each bag has m mollies and one b
KIM [24]

An algebraic expression that represent how much Mr. Green paid in all is 3(m + 1) + d

<h3 /><h3>Pet fish</h3>

The following represents the items bought

  • Each bag has m mollies and 1 bala
  • He bought 3 of these bags

The expression that represents the items in a bag is:

Bag=m + 1\\

He bought 3 bags.

So, the total spent on pet fish is:

Total =3(m + 1)

<h3>Fish food</h3>

A box costs d dollars.

This means that, the total amount Mr Green spent in the store is:

Total =3(m + 1) + d

Read more about algebraic expressions at:

brainly.com/question/4344214

7 0
3 years ago
What is the LCD of these fractions and why 3/5 and 3/4​
Nataly_w [17]

Answer:

wedf

Step-by-step explanation:

affwa

3 0
3 years ago
Read 2 more answers
Decide whether quadrilateral ABCD with vertices 4(3,1), B(-1,-1) C(1,3), and D(5.5) is a rectangle, rhombus,square, or parallelo
Sergeeva-Olga [200]

Answer: rhombus

Step-by-step explanation:

By inspection, we can tell that there are no right angles, so we can determine it is not a square or a rectangle.

From the options, it is implied that it is a parallelogram, so to determine if it is a rhombus, we can determine if there is a pair of consecutive congruent sides.

By the distance formula,

AB=\sqrt{(-1-3)^{2}+(-1-1)^{2}}=\sqrt{16+4}=2\sqrt{5}\\BC=\sqrt{(-1-1)^{2}+(-1-3)^{2}}=\sqrt{4+16}=2\sqrt{5}

As AB=BC, there is indeed a pair of consecutive congruent sides, and thus the most specific classification is a <em>rhombus</em>

5 0
2 years ago
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