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3 years ago

PLEASE HELP IM TAKING THE TEXT NOW!!!!!!!!!!!!!!!!! Solve for x and y 3x+y=6 x+y=2

Mathematics

2 answers:

Over [174]3 years ago

5 0

Answer:

I'm glad you asked!

Step-by-step explanation:

Let's solve for y first.

$3x + y = 6$

Step 1: Add -3x to both sides.

$3x+y+-3x=6+-3x$

$y=-3x+6$

Answer:

$y=-3x+6$

Now let's solve for x

$3x+y=6$

Step 1: Add -y to both sides.

$3x+y+-y=6+-y$

$3x=-y+6$

Step 2: Divide both sides by 3.

$\frac{3x}{3} =\frac{-y+6}{3}$

$x=\frac{-1}{3} y+2$

Answer:

$x=\frac{-1}{3} y+2$

aev [14]3 years ago

3 0

Answer:

x = 2

y = 0

Step-by-step explanation:

Let’s solve the simultaneous equations.

3x + y = 6

x + y = 2

Solve for x in the second equation.

x = 2 - y

Put x as 2 - y in the first equation and solve for y.

3(2 - y) + y = 6

6 - 3y + y = 6

6 - 2y = 6

-2y = 0

y = 0/-2

y = 0

Put y as 0 in the first equation and solve for x.

3x + 0 = 6

3x = 6

x = 6/3

x = 2

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3 years ago

Read 2 more answers

This year the fifth grade collected 216 fewer plastic containers than the fourth grade.How many plastic containers did the fifth

kap26 [50]

Let number of plastic containers collected by fourth grade= x

Then number of plastic containers collected by fifth grade students=x-216

If number of plastic container collected by fifth grade is y

then number of plastic container collected by fourth grade=y+216

So, we can write it as follows

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7 0

3 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

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