Let’s say son’s age = S
Dad’s age = D
4 years ago, the son was (S-4) and dad now is three times that so D=3(S-4)
Expand that to get D=3S-12
In 12 years, the son will be (S + 12)
Dad will also be (D + 12) and he will be two times the sons age at that point so:
D + 12 = 2(S + 12)
Expand the right side:
D +12 = 2S + 24
Subtract 12 from both sides:
D = 2S + 12
So now D = 2S + 12 AND
D = 3S - 12
Since both equations equal “D”, they must then equal each other:
2S + 12 = 3S - 12
Do some algebra and you get S = 24
Plug this back into EITHER “D=“ equations to find D
D=2(24) +12
D=60
Answer: Third option is correct.
Step-by-step explanation:
Since we have given that
if f(x)=0
if we let y=f(x)
then,
y=0,
So, that means when f(x) touches the x-axis,
According to the graph, we get that
At x= -2 f(x)=0
As xi negative in Second quadrant , and here we can see that f(x) touches the x-axis and intersect it.
At x=1, f(x)=0
At x=3, f(x)=0.
In above cases 'x' is positive, so, x lies in First quadrant, here too f(x) crosses the x-axis twice.
Hence, Third option is correct.
Divide the current year by the previous year then multiply it by 100.
Answer:
5x - 7= -12
5x - 7+7 = -12+ 7
5x= -5
x= -1
Step-by-step explanation:
hope this helped
